Question

我想使用ACTION_SEND分享图片。所以基本上当用户点击图像并选择“共享图像”时，它应该发送所选的图像，因此，在测试时，我需要使用哪个应用程序与whatsapp，Facebook，电子邮件等共享。然后在选择其中任何一个时，它会显示“共享失败，请再试一次”。我似乎无法弄清楚为什么它不起作用。但是我有相同的代码用ACTION_VIEW全屏显示图像文件，这似乎很好但不是共享。

public void Onmulti2 (View view) {

    Intent share = new Intent(Intent.ACTION_SEND);

    share.setType("image/*");

    String imagePath = Environment.getExternalStorageDirectory()
            + "/ahmed.jpg";

    File imageFileToShare = new File(imagePath);

    Uri uri = Uri.fromFile(imageFileToShare);
    share.putExtra(Intent.EXTRA_STREAM, uri);

    startActivity(Intent.createChooser(share, "Share Image!"));

}

Answer 1

设置类型图像/ jpg而不是图像/ *

public void Onmulti2 (View view) {

Intent share = new Intent(Intent.ACTION_SEND);

share.setType("image/jpg");

String imagePath = Environment.getExternalStorageDirectory()
        + "/ahmed.jpg";

File imageFileToShare = new File(imagePath);

Uri uri = Uri.fromFile(imageFileToShare);
share.putExtra(Intent.EXTRA_STREAM, uri);

startActivity(Intent.createChooser(share, "Share Image!"));

}

Answer 2

这对我有用

首先将我的图像存储在外部存储空间

private void SaveImage(Bitmap finalBitmap) {

    String state = Environment.getExternalStorageState();
    if (Environment.MEDIA_MOUNTED.equals(state)) {

        String root = Environment.getExternalStorageDirectory().toString();
        File myDir = new File(root + "/saved_images");
        myDir.mkdirs();
        String fname = "image.jpg";
        File file = new File(myDir, fname);
        if (file.exists()) file.delete();
        try {
            FileOutputStream out = new FileOutputStream(file);
            finalBitmap.compress(Bitmap.CompressFormat.JPEG, 90, out);
            out.flush();
            out.close();

        } catch (Exception e) {
            e.printStackTrace();
        }

        MediaScannerConnection.scanFile(this, new String[]{file.toString()}, null,
                new MediaScannerConnection.OnScanCompletedListener() {
                    public void onScanCompleted(String path, Uri uri) {
                        Log.e("ExternalStorage", "Scanned " + path + ":");
                        Log.e("ExternalStorage", "-> uri=" + uri);
                    }
                });
    }
}

##。 ##

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    Bitmap img = BitmapFactory.decodeResource(getResources(), R.drawable.ahmed);
    SaveImage(img);

}

然后从外部存储加载我的图像，然后共享它。

    public void Onmulti2 (View view) {

    Intent share = new Intent(Intent.ACTION_SEND);
    share.setType("image/jpeg");
    share.putExtra(Intent.EXTRA_STREAM, Uri.parse("/storage/emulated/0/saved_images/image.jpg"));
    startActivity(Intent.createChooser(share, "Share image using"));
}

注释

从模拟器获取路径

01-29 23:25:47.478 32648-32659/com.company.integrations E/ExternalStorage: Scanned /storage/emulated/0/saved_images/image.jpg:
01-29 23:25:47.478 32648-32659/com.company.integrations E/ExternalStorage: -> uri=content://media/external/images/media/106290

Answer 3

第1步：首先添加权限

<uses-permission android:name="android.permission.WRITE_EXTERNAL_STORAGE"/>

第2步：修改

Intent share = new Intent(Intent.ACTION_SEND);
share.setType("image/jpeg");    
sharingIntent.putExtra(Intent.EXTRA_STREAM, Uri.parse(imagePath);

共享图像时出错

3 个答案:

注释