我想实现代码来创建一个宾果应用程序，它点击按钮点击数组中的字母。
如何在运行按钮单击时随机将数组元素（如数组（a，b，c））分配给这些3X3表格单元格。当我得到像abc一样的行或对角线时，我想增加计数值。
我开始但我无法实现代码。我能得到任何建议。
这是我的代码
<html>
<head>
<script>
function run(){
var grid = document.getElementById("grid");
for (var i = 0, row; row = grid.rows[i]; i++){
row.cells[0].textContent = rand();
row.cells[1].textContent = rand();
row.cells[2].textContent = rand();
}
score()
}
function rand(){
var text = new Array();
var possible = "MCS*";
return possible.charAt(Math.floor(Math.random() * possible.length));
}
function score(){
var Row = document.getElementById("grid");
var Cells = Row.getElementsByTagName("td");
alert(Cells[0].innerText);
alert(Cells[1].innerText);
alert(Cells[2].innerText);
alert(Cells[3].innerText);
alert(Cells[5].innerText);
alert(Cells[6].innerText);
alert(Cells[7].innerText);
alert(Cells[8].innerText);
}
</script>
</head>
<body>
<form metdod="post">
<table border="1" cellpadding="0" cellspacing="0" style="border-collapse: collapse" width="100"v id="grid">
<tr>
<td id="1-1" height="19" width="20%"> </td>
<td id="1-2" height="19" width="20%"> </td>
<td id="1-3" height="19" width="20%"> </td>
</tr>
<tr>
<td id="2-1" height="16" width="20%"> </td>
<td id="2-2" height="16" width="20%"> </td>
<td id="2-3" height="16" width="20%"> </td>
</tr>
<tr>
<td id="3-1" height="19" width="20%"> </td>
<td id="3-2" height="19" width="20%"> </td>
<td id="3-3" height="19" width="20%"> </td>
</tr>
</table>
<br><br>
<input type="button" onClick="return run();" value="run">
</form>
</body>
</html>
提前致谢..
答案 0 :(得分：1)
这是为每个单元格分配值的方法：
for(var row = 1; row <= 3; row++) {
for(var col = 1; col <= 3; col++ {
var id = '#'+ row + "-" + col;
$(id).html(/* put some content here */);
}
}
要分配随机数，请参阅Math.random()。如果将该值乘以10并将其向下舍入，则将得到0到9之间的整数。使用该值从数组中选择一个元素。
修改
因此，如果您有一个类似letters = [ "A", "B", "CD", "asum", 12, "whatsoever" ]的数组和一个随机数n，那么letters[n]将为您提供索引为n的数组元素。对于n == 2：letters[n] == "CD"
答案 1 :(得分：1)
<html>
<head>
<script>
var arr_num = ["1","2","3"];
var match =["123","234","345","567","678","111","222","333","444","555","666"];
function run(){
var counter =0;
var grid = document.getElementById("grid");
for (var i = 0, row; row = grid.rows[i]; i++){
row.cells[0].textContent = arr_num[getRandom()];
row.cells[1].textContent = arr_num[getRandom()];
row.cells[2].textContent = arr_num[getRandom()];
}
var a = getMatch();
for(var i=0;i<getMatch().length; i++){
if(match.indexOf(a[i]) > -1)
counter++;
}
document.getElementById("count").innerHTML = counter++;
}
function getMatch(){
var grid = document.getElementById("grid");
var match1 = [[]];
var match_dia =[];
var temp_dia1 = 0;
var temp_dia2 = 2;
var temp_dia3 = 0;
var temp_dia4 = 2;
var match_col = [];
for (var i = 0, row; row = grid.rows[i]; i++){
match1[match1.length++] = row.cells[0].textContent+row.cells[1].textContent+row.cells[2].textContent;
match1[match1.length++] = row.cells[2].textContent+row.cells[1].textContent+row.cells[0].textContent;
if(match_col.length != 0){
match_col[0] = match_col[0]+row.cells[0].textContent;
match_col[1] = match_col[1]+row.cells[1].textContent;
match_col[2] = match_col[2]+row.cells[2].textContent;
match_col[3] = row.cells[0].textContent+match_col[3];
match_col[4] = row.cells[1].textContent+match_col[4];
match_col[5] = row.cells[2].textContent+match_col[5];
}else{
match_col[0] = row.cells[0].textContent;
match_col[1] = row.cells[1].textContent;
match_col[2] = row.cells[2].textContent;
match_col[3] = row.cells[0].textContent;
match_col[4] = row.cells[1].textContent;
match_col[5] = row.cells[2].textContent;
}
if(match_dia.length != 0){
match_dia[0] = match_dia[0]+row.cells[temp_dia1++].textContent;
match_dia[1] = match_dia[1]+row.cells[temp_dia2--].textContent;
match_dia[2] = row.cells[temp_dia3++].textContent+match_dia[2];
match_dia[3] = row.cells[temp_dia4--].textContent+match_dia[3];
}else{
match_dia[0] = row.cells[temp_dia1++].textContent;
match_dia[1] = row.cells[temp_dia2--].textContent;
match_dia[2] = row.cells[temp_dia3++].textContent;
match_dia[3] = row.cells[temp_dia4--].textContent;
}
}
for(var i=0;i<match_col.length;i++){
match1[match1.length++] = match_col[i];
}
match1[match1.length++] = match_dia[0];
match1[match1.length++] = match_dia[1];
return match1;
}
function getRandom(){
return Math.floor(Math.random() * arr_num.length) + 0 ;
}
</script>
</head>
<body>
<form metdod="post">
<table border="1" cellpadding="0" cellspacing="0" style="border-collapse: collapse" width="100"v id="grid">
<tr>
<td id="1-1" height="19" width="20%"> </td>
<td id="1-2" height="19" width="20%"> </td>
<td id="1-3" height="19" width="20%"> </td>
</tr>
<tr>
<td id="2-1" height="16" width="20%"> </td>
<td id="2-2" height="16" width="20%"> </td>
<td id="2-3" height="16" width="20%"> </td>
</tr>
<tr>
<td id="3-1" height="19" width="20%"> </td>
<td id="3-2" height="19" width="20%"> </td>
<td id="3-3" height="19" width="20%"> </td>
</tr>
</table>
<br><br>
<div id="count" name="count"></div>
<br><br>
<input type="button" onClick="return run();" value="run">
</form>
</body>
</html>
答案 2 :(得分：0)
这不是宾果游戏，而是你的＆＃34;将随机字母a，b，c分配给网格中的空格＆＃34;可以满足：
<Connector>现在，如果您真的想要模拟BINGO，其中列变化，列中的NUMBERS因给定序列而异，这是一个不同的问题;请注意，您需要有一个算法来分配玩家卡，而另一个算法则需要从列表中选择随机值来进行游戏＆＃34;卡两者都需要考虑范围和以前填充的值来排除重复 - 可行但是完全不同的问题。