Question

我已经创建了一个创建缩略图的php函数，它可以像现在一样工作但现在我想在mymysqli数据baze中插入这个缩略图和一些数据。我试着这样做，但它不起作用。我对mysql不好，需要帮助。

require 'config.php';

if(preg_match('/[.](jpg)$/', $filename)) {
    $im = imagecreatefromjpeg($path_to_image_directory . $filename);
} else if (preg_match('/[.](gif)$/', $filename)) {
    $im = imagecreatefromgif($path_to_image_directory . $filename);
} else if (preg_match('/[.](png)$/', $filename)) {
    $im = imagecreatefrompng($path_to_image_directory . $filename);
}

$ox = imagesx($im);
$oy = imagesy($im);

$nx = $final_width_of_image;
$ny = floor($oy * ($final_width_of_image / $ox));

$nm = imagecreatetruecolor($nx, $ny);

imagecopyresized($nm, $im, 0,0,0,0,$nx,$ny,$ox,$oy);

if(!file_exists($path_to_thumbs_directory)) {
  if(!mkdir($path_to_thumbs_directory)) {
       die("There was a problem. Please try again!");
  } 
   }
imagejpeg($nm, $path_to_thumbs_directory . $filename);
$host = 'localhost';
$user = 'timoleon_pandess';
$pass = 'pass';
mysql_connect($host, $user, $pass);
mysql_select_db('timoleon_pandessia');

$insert_path="INSERT INTO `ng17p_jshopping_products`(`product_id`,      `parent_id`, `product_ean`, `product_availability`, `product_template`,  `product_price`, `min_price`, `different_prices`, `product_weight`, `image`) VALUES ([value-1],[value-2],[value-3],[value-4],[value-5],[value-6],[value-7],[value-8],[value-9],[value-10])";

$var=mysql_query($inser_path);
?>

Answer 1

将数据库路径放入图像，例如：'\ img \ image2.png'

将表格更改为商店图片的类型“longb”（将触发LONGBLOB）。读这个 http://forums.mysql.com/read.php?20,17671,27914

为什么要在DB中插入图像？这样做

   Insert into table (`path`) Values ('image.png');

\image.png - 服务器上的图像路径。从DB读取时，您可以添加完整路径\img\avatar\image.png

我不明白，你使用插件查询就像是用php编写的吗？该值需要包含在''例如：不是,[value-4]而是,'[value-4]'中。我认为价值将是一个变量$value4。

  INSERT INTO `ng17p_jshopping_products` (`product_id`,    `parent_id`, `product_ean`, `product_availability`, `product_template`,  `product_price`, `min_price`, `different_prices`, `product_weight`, `image`) VALUES ('[value-1]','[value-2]','[value-3]','[value-4]','[value-5]','[value-6]','[value-7]','[value-8]','[value-9]','[value-10]')

Answer 2

你需要添加变量女巫将包含图像的文件名。

const char* empty() { return ""; }

char* message;
if(m_message)
    message = m_message;
else
    message = empty();

插入时

$filename=$path_to_thumbs_directory.$filename;

如果你完成所有操作并且在尝试更改代码以使用mysql i 时它会起作用，请在此处阅读$query="INSERT INTO `ng17p_jshopping_products` (`product_id`,`parent_id`,`product_ean`, `product_availability`,`product_template`, `product_price`, `min_price`, `different_prices`, `product_weight`, `image`) VALUES ('[value-1]','[value-2]','[value-3]','[value-4]','[value-5]','[value-6]','[value-7]','[value-8]','[value-9]','$filename')"; $res=mysql_query($query); if($res==1) { $id=mysql_insert_id; $query="Select image from ng17p_jshopping_products where id='$id'"; $res=mysql_query($query); $row=mysql_fetch_array($res); echo 'It is OK <img src="'.$row['image'].'">'; } else echo 'Error';

Answer 3

你必须使用ob_start（）; ob_get_clean（）;获取图像内容并将其放入数据库中。

首先在您的数据库中创建一个字段来存储图像内容：

ALTER TABLE `ng17p_jshopping_products` ADD `image_content` LONGBLOB NOT NULL ;

并使用您的代码：

<?php
require 'config.php';

if(preg_match('/[.](jpg)$/', $filename)) {
    $im = imagecreatefromjpeg($path_to_image_directory . $filename);
} else if (preg_match('/[.](gif)$/', $filename)) {
    $im = imagecreatefromgif($path_to_image_directory . $filename);
} else if (preg_match('/[.](png)$/', $filename)) {
    $im = imagecreatefrompng($path_to_image_directory . $filename);
}

$ox = imagesx($im);
$oy = imagesy($im);

$nx = $final_width_of_image;
$ny = floor($oy * ($final_width_of_image / $ox));

$nm = imagecreatetruecolor($nx, $ny);

imagecopyresized($nm, $im, 0,0,0,0,$nx,$ny,$ox,$oy);

if(!file_exists($path_to_thumbs_directory)) {
  if(!mkdir($path_to_thumbs_directory)) {
       die("There was a problem. Please try again!");
  } 
}

$host = 'localhost';
$user = 'timoleon_pandess';
$pass = 'pass';
mysql_connect($host, $user, $pass);
mysql_select_db('timoleon_pandessia');

ob_start();
imagejpeg($nm);
$image_content = mysql_real_escape_string(base64_encode(ob_get_clean()));
imagedestroy($nm);

$insert_path="INSERT INTO `ng17p_jshopping_products`(`product_id`, `parent_id`, `product_ean`, `product_availability`, `product_template`,  `product_price`, `min_price`, `different_prices`, `product_weight`, `image`,`image_content`) VALUES ([value-1],[value-2],[value-3],[value-4],[value-5],[value-6],[value-7],[value-8],[value-9],[value-10],'".$image_content."')";

$var=mysql_query($inser_path);
mysql_close();
?>

要显示图像，您必须使用以下功能：

<?php
function show_image($id) {
    $host = 'localhost';
    $user = 'timoleon_pandess';
    $pass = 'pass';
    mysql_connect($host, $user, $pass);
    mysql_select_db('timoleon_pandessia');

    // code to retrieve the image from database with $id id to $image_to_show variable
    // ....

    header('Content-Type: image/jpeg');
    echo stripslashes(base64_decode($image_to_show["image_content"]));
}
?>

Answer 4

这足以在项目与图像之间建立连接。设置为单元格，你将图像的路径存储到varchar（255）而不是blob或其他情况下的其他情况（存储文件不在硬盘上但在DB中）

$bd_host="localhost"; 
$bd_user="timoleon_pandess";
$bd_password="pass";
$bd_base="_base";

$con=mysql_connect($bd_host, $bd_user, $bd_password); 

if(!con) {
echo 'Ошибка, невозможно подключиться к серверу базы данных.'; 
exit; 
}

mysql_select_db($bd_base, $con); 
mysql_query('SET NAMES utf8');

$filename='/img/img.png'; // you need to catch it when you make and save thumbnail

$query="insert into ng17p_jshopping_products (`image`) Values ('$filename')";
mysql_query($query);

如果您的脚本没有制作图像或将其保存在需要的地方，这是另一个问题！

php在mysql表中插入数据

4 个答案: