无法在angularjs中选择加载选项值

时间:2016-01-29 08:48:15

标签: javascript angularjs

当设置search_dropdown值时,使用所选值作为索引需要设置filterText下拉列表的值。

<div class="form-group" data-ng-repeat="filter in filtersArray track by $index">
                <select name="search_dropdown"
                        ng-model="search_dropdown[filter]"
                        class="form-control">
                    <option value="">Select Filter Field</option>
                    <option data-ng-repeat="t in list_fields" value="{{t.field}}">{{t.displayName}}</option>
                </select>
            <select name="filterText" class="form-control" ng-model="filterText[filter]">
                <option value="">Select Filter Text</option>
                <option data-ng-repeat="t in list['{{search_dropdown[filter]}}'] track by $index" value="{{t}}">{{t}}</option>
            </select>

search_dropdown = ['name','description']和值  list['name'] = ['A','B'] and list['description'] = ['C','D']其中list是一个对象。

<option data-ng-repeat="t in list['{{search_dropdown[filter]}}'] 
track by $index" value="{{t}}">{{t}}</option>

这里如何设置filterText下拉列表的值,当在search_dropdown中选择名称时选择A,B,选择描述时选择C,D?

0 个答案:

没有答案