Question

import java.util.*;

public class Lock {
    private int combination = 1729;
    private int input;
    int[] code = new int[4];

    public void push(int button){
        for(int i = 0; i < 4; i++){
            code[i] = button;
        }
    }
    public boolean open(){
        boolean results = false;
        int boop = 0;
        for (int i = 0;i < 4; i++){
            boop = boop*10 + code[i];
        }
        if(boop == combination){
            results = true;
        }
        return results;
    }
}
And here is the tester

public class LockTester
{
   public static void main(String[] args)
   {
      Lock myLock = new Lock();
      myLock.push(1);
      myLock.push(7);
      myLock.push(3);
      myLock.push(9);
      System.out.println(myLock.open());
      System.out.println("Expected: false");
      myLock.push(1);
      myLock.push(7);
      myLock.push(2);
      myLock.push(9);
      System.out.println(myLock.open());
      System.out.println("Expected: true");
      myLock.push(1);
      myLock.push(7);
      myLock.push(2);
      System.out.println(myLock.open());
      System.out.println("Expected: false");
      myLock.push(9);
      System.out.println(myLock.open());
      System.out.println("Expected: false");
      myLock.push(1);
      myLock.push(7);
      myLock.push(2);
      myLock.push(9);
      System.out.println(myLock.open());
      System.out.println("Expected: true");
   }
}

我每次都会变得虚假。我不确定push方法是否正确填充数组。

Answer 1

在您当前的方法中，每次按下按钮时，您都会将所有4个按钮分配到同一输入。要解决此问题，您需要保持一些内部状态，表示锁中已按下哪些键按钮。在我的处理方法中，用户可以按下4个组合按钮，尝试打开锁定会将键盘重置为原始状态：

public class Lock {
    private int combination = 1729;
    private static int CODE_LENGTH = 4;
    private int input = 0;       // this will keep track of which button to press
    int[] code = new int[CODE_LENGTH];

    public void push(int button){
        if (input >= CODE_LENGTH) {
            System.out.println("All keys have been entered.  Please try to open the lock.");
            return;
        }

        // assign a single button press here
        code[input] = button;
        ++input;
    }

    public boolean open() {
        input = 0;    // reset the keypad to its initial state here
        int boop = 0;
        for (int i=0; i < CODE_LENGTH; i++) {
            boop = boop*10 + code[i];
        }
        if (boop == combination) {
            return true;
        }

        return false;
    }
}

Answer 2

(c * 100) + 32

这部分代码看起来不对。当您使用public void push(int button){ for(int i = 0; i < 4; i++){ code[i] = button; } }推送数组的每个元素时，数组将在所有索引上填充n。在代码中看起来像

之后

myLock.push(n)

你期待数组是[1,7,3,9]。但实际上它将是[9,9,9,9]。

你可以试试这个。

  myLock.push(1);
  myLock.push(7);
  myLock.push(3);
  myLock.push(9);

Push方法填充数组

2 个答案: