Question

我在运行phpunit测试时遇到此错误：

SQLSTATE[23000]: Integrity constraint violation: 1048 Column 'profile_id' cannot be null (SQL: insert into `comments` (`description`, `status`, `profile_id`, `project_id`, `updated_at`, `created_at`) values (Awesome Comment, active, , 21, 2016-01-29 00:05:21, 2016-01-29 00:05:21))

正如您所看到的那样，它为profile_id发送了一个空ID，我在创建注释之前创建了配置文件。这是我的测试代码：

public function testProjectCommentCreation()
{
    $category = factory(\App\Category::class)->create();
    $category->projects()->save(factory(\App\Project::class)->make());


    $profile = factory(\App\Profile::class)->make([
        'name' => 'John',
        'last_name' => 'Snow',
        'skills' => 'php'
    ]);

    $category->projects[0]->comments()->save(factory(\App\Comment::class)->make([
        'description'=>'Awesome Comment',
        'status'=>'active',
        'profile_id'=>$profile->id
    ]));

    $this->post(route('api.projects.comments.store', ["projects" => $category->projects[0]->id]), $category->projects[0]->comments->jsonSerialize(), $this->jsonHeaders)
        ->seeInDatabase('comments', ['project_id' => $category->projects[0]->id])
        ->assertResponseOk();
}

一个项目属于一个类别，一个注释属于一个项目和一个配置文件，所以我需要发送外键值profile_id和project_id，问题是我不知道如何检索配置文件的id我创造了。

这些是我使用的工厂：

$factory->define(App\Profile::class, function (Faker\Generator $faker) {
return [
    'name' => $faker->name,
    'last_name' => $faker->name,
    'status' => 'active',
    'avatar' => str_random(10),
    'skills'=> str_random(10),
    'notifications'=>'on'
];
});

$factory->define(App\Comment::class, function (Faker\Generator $faker) {
return [
    'description' => str_random(10),
    'status' => 'active',
    'profile_id' => 1,
    'project_id' => 1
];});

$factory->define(App\Category::class, function (Faker\Generator $faker) {
return [
    'description' => str_random(10),
    'status' => 'active'
];});

$factory->define(App\Project::class, function (Faker\Generator $faker) {
return [
    'description' => str_random(10),
    'status' => 'active',
    'privacy' => 'false'
];});

我已经测试了每种类型对象的构造并且它正在工作，我失败的是创建一个注释，因为我需要首先创建一个配置文件并检索id并且出于某种原因使用$ profile-＆gt ; id正在拉空

Answer 1

问题是，在使用make()时，您的个人资料未保存到数据库中。

为了能够使用/分配来自profile_id的外键$profile，您需要create()工厂模型，而不仅仅是make()。< / p>

$profile = factory(\App\Profile::class)->create([
    'name' => 'John',
    'last_name' => 'Snow',
    'skills' => 'php'
]);

这应该可以解决问题。

Laravel，phpunit由于空外键

1 个答案: