PHP连接到数据库(没有输出!)

时间:2016-01-28 20:45:07

标签: php html oracle

我编写了一个代码来将html页面连接到数据库,但它不会搜索表中的所有员工。我不确定为什么代码似乎是正确的。它不会给出任何错误或警告。

任何人都可以向我解释有什么问题吗?

<div>
  <form id='searchform' action='index.php' method='get'>
    <a href='index.php'>All employees</a> ---
    Search by a last name:
    <input id='search' name='search' type='text' size='20' value='<?php echo @$_GET['search']; ?>' />
    <input id='submit' type='submit' value='Go!' />
  </form>
</div>


<?php
  // check if search view of list view
  if (isset($_GET['search'])) {
    $sql = "SELECT * FROM Employee WHERE LastName like '%" . @$_GET['search'] . "%'";
  } else {
    $sql = "SELECT * FROM Employee";
  }

  // execute sql statement
  $stmt = oci_parse($conn, $sql);
  oci_execute($stmt);
?>


<table style='border: 1px solid #DDDDDD'>
  <thead>
    <tr>
      <th>Personal Number</th>
      <th>Insurance Number</th>
      <th>First Name</th>
      <th>Last Name</th>
      <th>Birth Date</th>
      <th>Gender</th>
      <th>Hire Date</th>
      <th>Salary</th>
      <th>Office ID</th>
    </tr>
  </thead>
  <tbody>


<?php
  // fetch rows of the executed sql query
  while ($row = oci_fetch_assoc($stmt)) {
    echo "<tr>";
    echo "<td>" . $row['PersonalNumber'] . "</td>";
    echo "<td>" . $row['InsuranceNumber'] . "</td>";
    echo "<td>" . $row['FirstName'] . " " . $row['LastName'] . "</td>";
    echo "<td>born on " . $row['BirthDate'] . "</td>";
    echo "<td>" . $row['Gender'] . "</td>";
    echo "<td>hired on " . $row['HireDate'] . "</td>";
    echo "<td>" . $row['Salary'] . "</td>";
    echo "<td>" . $row['OfficeID'] . "</td>";
    echo "</tr>";
  }
?>

  </tbody>
  </table>

<div>There are found <?php echo oci_num_rows($stmt); ?> employees!</div>

<?php  oci_free_statement($stmt); ?>

</body>

0 个答案:

没有答案