Question

我有以下格式的JSON：

{
  "id": 1913548255,
  "notification": "NotificationReceived",
  "deviceGuid": "e60d6085-2aba-48e9-b1c3-73c673e414be",
  "timestamp": "2016-01-28T20:34:34.167",
  "parameters": {
    "jsonString": "{\"mac\":\"bc6a29abd973\",\"uuid\":\"f000aa1104514000b000000000000000\",\"value\":0.27328648477047685}"
  }
}

我想反序列化它以获得以下类，以便：

case class Parameters(mac: String, uuid: String, value: Double)
case class Notification(id: BigInt, notification: String, deviceGuid: String, timestamp: String, perameters: Parameters)

我知道我需要写CustomSerializer。但我没有太多经验。请指导我。谢谢你的帮助。

Answer 1

我决定不处理反序列化器，但是以普通方式进行处理。我发布的代码是为了帮助某人。

case class Parameters(mac: String, uuid: String, value: Double)
case class Notification(id: Int, notification: String, deviceGuid: String, timestamp: String, parameters: Map[String, String])
case class FinalNotification(id: Int, notification: String, device_guid: String, timestamp: String, mac: String, uuid: String, value: Double)

 implicit val formats = DefaultFormats
 val n = parse(v).extract[Notification]

 def convertJson(json: Option[String]): Parameters = json match {
    case None => throw new IllegalArgumentException("Json can't be converted. ")
    case Some(j) => parse(j).extract[Parameters]
}

val param = convertJson(n.parameters.get("jsonString"))

FinalNotification(n.id, n.notification, n.deviceGuid, n.timestamp, param.mac, param.uuid, param.value)

使用JSON4S反序列化JSON

1 个答案: