我正在尝试为多个用户创建聊天室。 所以，我所做的是创建一个类（＆＃34; Lists＆＃34;），添加用户（＆＃34; user1＆＃34; - ＆＃34; user10＆＃34;）然后当然给了他们objectId。 我现在做的是检查类中的用户是否与当前用户匹配，以便仅在其中一个用户帐户上显示此类。我用谓词做了那个。问题是谓词格式无法处理带有> 4个子预测值的OR（这也是Parse文档指南中的内容）。
当我拿出5-10个用户时，一切都按照应有的方式工作，问题是该组最多只能有四个用户。如果有可能避免在当前状态下使用pred，那么一切都将是完美的。
错误（在控制台中）：
此查询过于复杂。它之后有一个带有＆gt; 4个子预测的OR 正常化。
这是我的代码：
func loadGroups() {
grooms = [PFObject]()
users = [PFUser]()
self.tableView.reloadData()
let pred = NSPredicate(format: "user1 = %@ OR user2 = %@ OR user3 = %@ OR user4 = %@ OR user5 = %@ OR user6 = %@ OR user7 = %@ OR user8 = %@ OR user9 = %@ OR user10 = %@", PFUser.currentUser() !, PFUser.currentUser() !, PFUser.currentUser() !, PFUser.currentUser() !, PFUser.currentUser() !, PFUser.currentUser() !, PFUser.currentUser() !, PFUser.currentUser() !, PFUser.currentUser() !, PFUser.currentUser() !)
let groomQuery = PFQuery(className: "Lists", predicate: pred)
groomQuery.orderByAscending("lastUpdate")
groomQuery.includeKey("user1")
groomQuery.includeKey("user2")
if groomQuery.includeKey("user3") != "" {
groomQuery.includeKey("user3")
}
if groomQuery.includeKey("user4") != "" {
groomQuery.includeKey("user4")
}
if groomQuery.includeKey("user5") != "" {
groomQuery.includeKey("user5")
}
if groomQuery.includeKey("user6") != "" {
groomQuery.includeKey("user6")
}
if groomQuery.includeKey("user7") != "" {
groomQuery.includeKey("user7")
}
if groomQuery.includeKey("user8") != "" {
groomQuery.includeKey("user8")
}
if groomQuery.includeKey("user9") != "" {
groomQuery.includeKey("user9")
}
if groomQuery.includeKey("user10") != "" {
groomQuery.includeKey("user10")
}
SwiftLoader.show(true)
groomQuery.findObjectsInBackgroundWithBlock {
(results: [AnyObject] ? , error : NSError ? ) - > Void in
if error == nil {
SwiftLoader.hide()
print("found everything", terminator: "")
self.grooms = results as![PFObject]
for groom in self.grooms {
let user1 = groom.objectForKey("user1") as!PFUser
let user2 = groom["user2"] as!PFUser
if groom["user3"] != nil {
self.user3 = groom["user3"] as!PFUser
}
if groom["user4"] != nil {
self.user4 = groom["user4"] as!PFUser
}
if groom["user5"] != nil {
self.user5 = groom["user5"] as!PFUser
}
if groom["user6"] != nil {
self.user6 = groom["user6"] as!PFUser
}
if groom["user7"] != nil {
self.user7 = groom["user7"] as!PFUser
}
if groom["user8"] != nil {
self.user8 = groom["user8"] as!PFUser
}
if groom["user9"] != nil {
self.user9 = groom["user9"] as!PFUser
}
if groom["user10"] != nil {
self.user10 = groom["user10"] as!PFUser
}
if user1.objectId != PFUser.currentUser() !.objectId {
self.users.append(user1)
print("append user1", terminator: "")
}
if user2.objectId != PFUser.currentUser() !.objectId {
self.users.append(user2)
}
if self.user3 != nil {
if self.user3.objectId != PFUser.currentUser() !.objectId {
self.users.append(self.user3)
}
}
if self.user4 != nil {
if self.user4.objectId != PFUser.currentUser() !.objectId {
self.users.append(self.user4)
}
}
if self.user5 != nil {
if self.user5.objectId != PFUser.currentUser() !.objectId {
self.users.append(self.user5)
}
}
if self.user6 != nil {
if self.user6.objectId != PFUser.currentUser() !.objectId {
self.users.append(self.user6)
}
}
if self.user7 != nil {
if self.user7.objectId != PFUser.currentUser() !.objectId {
self.users.append(self.user7)
}
}
if self.user8 != nil {
if self.user8.objectId != PFUser.currentUser() !.objectId {
self.users.append(self.user8)
}
}
if self.user9 != nil {
if self.user9.objectId != PFUser.currentUser() !.objectId {
self.users.append(self.user9)
}
}
if self.user10 != nil {
if self.user10.objectId != PFUser.currentUser() !.objectId {
self.users.append(self.user10)
}
}
}
self.tableView.reloadData()
self.groomArray = self.grooms
}
}
最相关的一行：
let pred = NSPredicate(format: "user1 = %@ OR user2 = %@ OR user3 = %@ OR user4 = %@ OR user5 = %@ OR user6 = %@ OR user7 = %@ OR user8 = %@ OR user9 = %@ OR user10 = %@", PFUser.currentUser()!, PFUser.currentUser()!, PFUser.currentUser()!, PFUser.currentUser()!, PFUser.currentUser()!, PFUser.currentUser()!, PFUser.currentUser()!, PFUser.currentUser()!, PFUser.currentUser()!, PFUser.currentUser()!)
我的问题：
是否可以避免和交换上面的代码行以使其工作？或者通过关系来做这一切会更有效率吗？有什么提示吗？
提前致谢，对于有关代码或任何问题的任何问题，请发表评论。