我一直在努力在NSArray中循环解析它然后将它添加到NSMutableArray。问题不在于解析我想循环遍及整个NSArray。
这是我的代码:
if let dictionarys : NSArray = dictionary.valueForKey("response") as? NSArray {
var categoryNum = 0
var currency = "0"
if let category: NSArray = dictionarys.valueForKey("category") as? NSArray {
if let catId = category.valueForKey("categoryID") as? NSArray {
categoryNum = catId[0] as! Int
}
}
if let currency1: NSArray = dictionarys.valueForKey("currency") as? NSArray {
if let currency2 = currency1[0] as? String {
currency = currency2
}
}
serviceObject = ServicesObject(categoryId: categoryNum,currency: currency)
CategoryItems.addObject(serviceObject)
}
self.tableView.reloadData()
我想做这样的事情:
for (var i = 0;i<dictionarys.count ; i++){
var categoryNum = 0
var currency = "0"
if let category: NSArray = dictionarys.valueForKey("category") as? NSArray {
if let catId = category.valueForKey("categoryID") as? NSArray {
categoryNum = catId[0] as! Int
}
}
if let currency1: NSArray = dictionarys.valueForKey("currency") as? NSArray {
if let currency2 = currency1[0] as? String {
currency = currency2
}
}
serviceObject = ServicesObject(categoryId: categoryNum,currency: currency)
CategoryItems.addObject(serviceObject)
}
我正在尝试解析的一个示例:print(dictionarys)
(
{
category = {
category = "<null>";
categoryID = 66;
};
currency = 2;
},{
category = {
category = "<null>";
categoryID = 66;
};
currency = 2;
},{
category = {
category = "<null>";
categoryID = 66;
};
currency = 2;
}
)
答案 0 :(得分:1)
我已经采用了您的JSON示例,并为您提供了一个非常简单的示例,让您了解正确的Swift循环,这可能是您需要适应实际代码库和数据的。
鉴于&#34; dictionarys&#34;是NSDictionaries的NSArray:
sort: {}
答案 1 :(得分:1)
我让你的例子更加Swifty并添加了一些模拟类来让它在一个简单的Playground中运行:
import Foundation
class ServicesObject {
var categoryId: Int
var currency: String
init(categoryId: Int, currency: String) {
self.categoryId = categoryId
self.currency = currency
}
}
class CategoryItems {
static func addObject(item: ServicesObject) {
print("Added categoryID \(item.categoryId), currency \(item.currency)")
}
}
let dictionary: NSArray = [
["response":
["category":
["category":"<null>",
"categoryID":66],
"currency": "2"]],
["response":
["category":
["category":"<null>",
"categoryID":67],
"currency": "3"]],
["response":
["category":
["category":"<null>",
"categoryID":68],
"currency": "4"]]]
if let responses = dictionary.valueForKey("response") as? NSArray {
for response in responses where response is NSDictionary { // loop over all responses
var categoryNums = 0
if let category = response["category"] as? NSDictionary {
categoryNums = category["categoryID"] as? Int ?? 0
}
var currency = response["currency"] as? String ?? "0"
let serviceObject = ServicesObject(categoryId: categoryNums, currency: currency)
CategoryItems.addObject(serviceObject) // add all responses
}
}
那里有一些比较漂亮的东西,例如nil coalescing operator (??
),但希望它可以作为一个例子。
答案 2 :(得分:0)
如果您尝试这样做,可以使用其他数组初始化数组。
var nsmutablearrayVariableName = NSMutableArray.init(array: nsarrayVariableName)