Question

获取此代码以将新产品上传到数据库由于我是php的新手，我从几个来源复制了它一切似乎都在这个地方，语法也没问题，但在上传图片时仍然没有成功。将数据插入db

UPLOAD.php页面 -

<?php
require "dbconn.php";
require "functions.php";

if(isset($_POST['Submit']))
{

     $product_name = strip_tags($_POST['name']);
     $product_price = strip_tags($_POST['price']);
     $category = strip_tags($_POST['category']);

}

$target_dir = "img/'.$category.'/";
$target_file = $target_dir . basename($_FILES["fileToUpload"]["name"]);
$uploadOk = 1;
$imageFileType = pathinfo($target_file,PATHINFO_EXTENSION);
// Check if image file is a actual image or fake image
if(isset($_POST["submit"])) {
    $check = getimagesize($_FILES["fileToUpload"]["tmp_name"]);
    if($check !== false) {
        echo "File is an image - " . $check["mime"] . ".";
        $uploadOk = 1;
    } else {
        echo "File is not an image.";
        $uploadOk = 0;
    }
}
// Check if file already exists
if (file_exists($target_file)) {
    echo "Sorry, file already exists.";
    $uploadOk = 0;
}
// Check file size
if ($_FILES["fileToUpload"]["size"] > 500000) {
    echo "Sorry, your file is too large.";
    $uploadOk = 0;
}
// Allow certain file formats
if($imageFileType != "jpg" && $imageFileType != "png" && $imageFileType != "jpeg"
&& $imageFileType != "gif" ) {
    echo "Sorry, only JPG, JPEG, PNG & GIF files are allowed.";
    $uploadOk = 0;
}
// Check if $uploadOk is set to 0 by an error
if ($uploadOk == 0) {
    echo "Sorry, your file was not uploaded.";
// if everything is ok, try to upload file
} else {
    if (move_uploaded_file($_FILES["fileToUpload"]["tmp_name"], $target_file)) {
        insert_new_product($product_name, $product_price, $target_file, $category);
        header("Location: add_product.php?cname=$category");
    } else {
        echo "Sorry, there was an error uploading your file.";
    }
}

?>

HTML

<table>

<form action="upload.php" method="post" enctype="multipart/form-data">
<tr>
<td>
<input name="name" type="text">Name:</br>
</td>
</tr>

<tr>
<td>
<input name="price" type="text">Price:</br>
</td>
</tr>

<tr>
<td>
<input name="category" value="<?php echo $category; ?>" type="hidden">
</td>

</tr>

<tr>

    Choose the file:
    <input type="file" name="fileToUpload" id="fileToUpload">
    <input type="submit" value="Upload Image" name="submit">
</form>
</table>

Answer 1

我建议你改变

$target_dir = "img/'.$category.'/";

到

$target_dir = "img/".$category."/";

此外，尝试查看提交表单时请求的去向。理想情况下，您需要一个基本标记来指定PHP控制器作为没有完整路径的表单操作。

使用php将图像和数据上传到数据库

1 个答案: