我正在尝试使用LISTAGG()来获取两列以上的内容。
SELECT deptname, deptno, LISTAGG(ename, ',') WITHIN GROUP (ORDER BY ename) AS employees
FROM emp
GROUP BY deptno;
但它抛出了这个错误:
: FROM keyword not found where expected
00000 - "FROM keyword not found where expected"
*Cause:
*Action:
Error at Line: 3 Column: 12
可以请有人解释原因吗?
答案 0 :(得分:3)
LISTAGG 分析功能是在 Oracle 11g第2版中引入的。因此,如果您使用的是旧版本,则无法使用它。
错误似乎很奇怪。您实际应该得到ORA-00904: "DEPTNAME": invalid identifier
,因为EMP
架构中的标准SCOTT
表没有DEPTNAME列。此外,您应该获得ORA-00979: not a GROUP BY expression
,因为您没有在 GROUP BY 表达式中提及 SELECT ed列。
使用 SCOTT 架构中的标准 EMP 表:
SQL> SELECT deptno,
2 job,
3 LISTAGG(ename, ',') WITHIN GROUP (
4 ORDER BY ename) AS employees
5 FROM emp
6 GROUP BY deptno,
7 job;
DEPTNO JOB EMPLOYEES
---------- --------- ------------------------
10 CLERK MILLER
10 MANAGER CLARK
10 PRESIDENT KING
20 CLERK ADAMS,SMITH
20 ANALYST FORD,SCOTT
20 MANAGER JONES
30 CLERK JAMES
30 MANAGER BLAKE
30 SALESMAN ALLEN,MARTIN,TURNER,WARD
9 rows selected.
SQL>
答案 1 :(得分:2)
尝试:
SELECT deptname, deptno, LISTAGG(ename, ',') WITHIN GROUP (ORDER BY ename) AS employees
FROM emp
GROUP BY deptno,deptname;
答案 2 :(得分:0)
Oracle 11g:
SELECT deptname, deptno, LISTAGG(ename, ',') WITHIN GROUP (ORDER BY deptno,job) AS employees
FROM emp
GROUP BY deptno,job;
Oracle 10g:
SELECT deptname, deptno, WMSYS.WM_CONCAT(ename) AS employees
FROM emp
GROUP BY deptno,job;