如何将视频更快地上传到php服务器

Question

我已经捕获了3MB视频并将其保存到我的Android设备SD卡，我从设备中选择它并想将其传输到php服务器。上传工作完美，但需要很长时间，甚至3mb视频上传需要4-5分钟，即使我也有快速的互联网连接。那么有没有办法更快地完成上传任务？或任何其他方式来做到这一点。非常感谢任何其他建议。在此先感谢：）

这是我的上传类连接和解析视频。

    try {
        FileInputStream fileInputStream = new FileInputStream(sourceFile);
        URL url = new URL(UPLOAD_URL);
        conn = (HttpURLConnection) url.openConnection();
      // conn.setFixedLengthStreamingMode(1024);
        conn.setDoInput(true);
        conn.setDoOutput(true);
        conn.setUseCaches(false);
        conn.setRequestMethod("POST");
        conn.setRequestProperty("Connection", "Keep-Alive");
        conn.setRequestProperty("ENCTYPE", "multipart/form-data");
        conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
        conn.setRequestProperty("myFile", fileName);
        dos = new DataOutputStream(conn.getOutputStream());
        dos.writeBytes(twoHyphens + boundary + lineEnd);
        dos.writeBytes("Content-Disposition: form-data; name=\"myFile\";filename=\"" + fileName + "\"" + lineEnd);
        dos.writeBytes(lineEnd);

        bytesAvailable = fileInputStream.available();
        Log.i("Huzza", "Initial .available : " + bytesAvailable);

        bufferSize = Math.min(bytesAvailable, maxBufferSize);
        buffer = new byte[bufferSize];

        bytesRead = fileInputStream.read(buffer, 0, bufferSize);

        while (bytesRead > 0) {
            dos.write(buffer, 0, bufferSize);
            bytesAvailable = fileInputStream.available();
            bufferSize = Math.min(bytesAvailable, maxBufferSize);
            bytesRead = fileInputStream.read(buffer, 0, bufferSize);
        }

        dos.writeBytes(lineEnd);
        dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);

        serverResponseCode = conn.getResponseCode();
        Toast.makeText(_context,"response code is " +serverResponseCode,Toast.LENGTH_SHORT).show();

        fileInputStream.close();
        dos.flush();
        dos.close();
    } catch (MalformedURLException ex) {
        ex.printStackTrace();
    } catch (Exception e) {
        e.printStackTrace();
    }

    if (serverResponseCode == 200) {
        StringBuilder sb = new StringBuilder();
        try {
            BufferedReader rd = new BufferedReader(new InputStreamReader(conn
                    .getInputStream()));
            String line;
            while ((line = rd.readLine()) != null) {
                sb.append(line);
            }
            rd.close();
        } catch (IOException ioex) {
        }
        return sb.toString();
    }else {
        return "Could not upload";
    }
}

}
这是我的后台任务的主要活动。

private void uploadVideo() {
    class UploadVideo extends AsyncTask<Void, Void, String> {

        ProgressDialog uploading;

        @Override
        protected void onPreExecute() {
            super.onPreExecute();
            uploading = ProgressDialog.show(MainActivity.this, "Uploading File", "Please wait...", false, false);
        }

        @Override
        protected void onPostExecute(String s) {
            super.onPostExecute(s);
            uploading.dismiss();
            textViewResponse.setText(Html.fromHtml("<b>Uploaded at <a href='" + s + "'>" + s + "</a></b>"));
            textViewResponse.setMovementMethod(LinkMovementMethod.getInstance());
        }

        @Override
        protected String doInBackground(Void... params) {
            Upload u = new Upload();
            String msg = u.uploadVideo(selectedPath,getApplicationContext());

            return msg;
        }
    }


    UploadVideo uv = new UploadVideo();
    uv.execute();
}