下面是我获得的json数据中的json字符串并转换为字符串。我需要提取order_id,order_number,price等值。
Optional({
msg = Success;
name = "Add Order";
"order_id" = 40509;
"order_number" = 012720380116;
"price" = 115;
status = 1;
})
我试图用NSJSONSerialization.JSONObjectWithData获取值,但没有给我任何东西。我的代码有什么问题,有人可以看看吗?
do {
let json:AnyObject? = try NSJSONSerialization.JSONObjectWithData(data!, options: .AllowFragments)
if let order_number = json!["order_number"] as? String {
print(order_number)
}
答案 0 :(得分:1)
你需要适当地施放。
let json = try
NSJSONSerialization.JSONObjectWithData(data!, options: .AllowFragments)
as! [String: AnyObject]
答案 1 :(得分:0)
最后,我在do-catch上使用了以下代码块,并且它正常工作
let jsonDict = try NSJSONSerialization.JSONObjectWithData(data2, options: NSJSONReadingOptions(rawValue: 0)) as? NSDictionary
if let stat = jsonDict!["status"] {
if stat as! NSObject == 1 {
let order_id = jsonDict!["order_id"]
let order_number = jsonDict!["order_number"]
let price = jsonDict!["price"]
}
}