Question

在我的网站上，我有

的常用路线

website.com
website.com/pages/about
website.com/img/116633
...

现在我有这些页面

website.com/username/mike
website.com/username/john
website.com/username/eric
...

应该成为

website.com/mike
website.com/john
website.com/eric
...

我的路由是这样的：

$routes->connect(
    '/*',
    ['controller' => 'username', 'action' => 'index'],
    ['routeClass' => 'DashedRoute']
);

这可行，但所有其他页面如

website.com/pages/about
website.com/img/116633

已被破坏（他们使用＆＃39;控制器＆＃39; =＆gt;＆＃39;用户名＆＃39;）

实现这一目标的最佳方法是什么？

在我的完整路线下面.php

    Router::defaultRouteClass('Route');

Router::extensions(['html', 'rss', 'pdf']);

Router::scope('/', function ($routes) {

    $routes->connect('/', ['controller' => 'Search', 'action' => 'start']);

    $routes->connect('/start', ['controller' => 'Search', 'action' => 'start']);

    $routes->connect(
        '/*',
        ['controller' => 'username', 'action' => 'index'],
        ['routeClass' => 'DashedRoute']
    );

    $routes->fallbacks('InflectedRoute');
});




Router::connect('/img/*', ['controller' => 'Pic', 'action' => 'item']);

Router::url([
    'controller' => 'Pages',
    'action' => 'lang',
    '_base' => 'false'
]);



Router::addUrlFilter(function ($params, $request) {
    if (isset($request->params['lang']) && !isset($params['lang'])) {
        $params['lang'] = $request->params['lang'];
    }
    return $params;
});


Plugin::routes();

Answer 1

 $routes->connect(
    '/*',
    ['controller' => 'username', 'action' => 'index'],
    ['routeClass' => 'DashedRoute']
);

必须替换为：

$routes->connect(
    '/:username',
    ['controller' => 'Username', 'action' => 'index'],
    [
      'pass' => ['username'],
        'username'  => '[0-9a-zA-Z]+'
    ]
);

这会将网址中的用户名传递给index()控制器中的Username。

有关详情，请访问：Route Elements和Passing parameters to Action。

cakephp 3.x路由到子文件夹

1 个答案: