我无法弄清楚如何为表使用别名(我认为别名是解决我问题的正确方法)。我有表SubContract有3个字段:SubcontractID,DivisionManager和ServiceManager。这两个字段都通过EmployeeID与同一个表Employee相关。表Employee包括EmployeeID和FirstName字段。我无法弄清楚如何同时显示DivisionManager和ServiceManager的FirstName。我使用这种方法但仍然没有工作:
$query = "SELECT SubContract.SubContractID, SubContract.DivisionManagerEmployeeID, Employee.FirstName, SubContract.ServiceManagerEmployeeID, Employee.FirstName FROM SubContract
INNER JOIN Employee Employee1 ON Employee1.EmployeeID = SubContract.DivisionManagerEmployeeID
INNER JOIN Employee Employee2 ON Employee2.EmployeeID = SubContract.ServiceManagerEmployeeID";
$stmt = $db->prepare($query);
$stmt->execute();
$stmt->store_result();
$numrows = $stmt->num_rows;
$stmt>bind_result($SubContractID,$DivisionManagerEmployeeID,$DivisionMangerFirstName, $ServiceManagerEmployeeID,$ServiceMangerFirstName);
任何帮助都会非常感激。
答案 0 :(得分:0)
我只想弄清楚:
SELECT SubContract.SubContractID, SubContract.DivisionManagerEmployeeID,DivisionManager.FirstName, SubContract.ServiceManagerEmployeeID, ServiceManager.FirstName
FROM SubContract
INNER JOIN Employee ServiceManager ON ServiceManager.EmployeeID = SubContract.ServiceManagerEmployeeID
INNER JOIN Employee DivisionManager ON DivisionManager.EmployeeID = SubContract.DivisionManagerEmployeeID