我想获取由边连接的顶点作为数组返回作为json中的属性。
例如:如果POST有10条评论,则查询应返回类似的内容。
{
@class: Post,
postTitle: "Some title",
comments: [
{
@class: Comment,
content: "First Comment,
someKey: "Some Value"
},
{
@class: Comment,
content: "Second Comment
someKey: "Some Value"
}
]
}
可以通过此查询获取数组中顶点的一个属性
select *, out('HAS_COMMENT').content as comments from POST
这将导致一个数组在Comment类
中只有'content'属性的值我需要将完整记录作为嵌套的json获取。
如果我在查询中使用out('HAS_COMMENT')
而不是out('HAS_COMMENT').content
,则会返回@rid
字段而不是完整记录。
答案 0 :(得分:2)
我尝试了这种结构:
create class Post extends V
create class Comment extends V
create class HAS_COMMENT extends E
create property Post.postTitle String
create property Comment.content String
create property Comment.someKey Integer
create vertex Post set postTitle="First"
create vertex Post set postTitle="Second"
create vertex Comment set content="First Comment", someKey="1"
create vertex Comment set content="Second Comment", someKey="2"
create vertex Comment set content="Third Comment", someKey="3"
create vertex Comment set content="Fourth Comment", someKey="4"
create vertex Comment set content="Fifth Comment", someKey="5"
create vertex Comment set content="Sixth Comment", someKey="6"
create vertex Comment set content="Seventh Comment", someKey="7"
create vertex Comment set content="Eighth Comment", someKey="8"
create vertex Comment set content="Ninth Comment", someKey="9"
create vertex Comment set content="Tenth Comment", someKey="10"
create vertex Comment set content="Eleventh Comment", someKey="11"
create vertex Comment set content="Twelfth Comment", someKey="12"
create vertex Comment set content="Thirteenth Comment", someKey="13"
create vertex Comment set content="Fourteenth Comment", someKey="14"
create edge HAS_COMMENT from (select from Post where postTitle="First") to (select from Comment where content="First Comment")
create edge HAS_COMMENT from (select from Post where postTitle="First") to (select from Comment where content="Second Comment")
create edge HAS_COMMENT from (select from Post where postTitle="First") to (select from Comment where content="Third Comment")
create edge HAS_COMMENT from (select from Post where postTitle="First") to (select from Comment where content="Fourth Comment")
create edge HAS_COMMENT from (select from Post where postTitle="First") to (select from Comment where content="Fifth Comment")
create edge HAS_COMMENT from (select from Post where postTitle="First") to (select from Comment where content="Sixth Comment")
create edge HAS_COMMENT from (select from Post where postTitle="First") to (select from Comment where content="Seventh Comment")
create edge HAS_COMMENT from (select from Post where postTitle="First") to (select from Comment where content="Eighth Comment")
create edge HAS_COMMENT from (select from Post where postTitle="First") to (select from Comment where content="Ninth Comment")
create edge HAS_COMMENT from (select from Post where postTitle="First") to (select from Comment where content="Tenth Comment")
create edge HAS_COMMENT from (select from Post where postTitle="Second") to (select from Comment where content="Eleventh Comment")
create edge HAS_COMMENT from (select from Post where postTitle="Second") to (select from Comment where content="Twelfth Comment")
create edge HAS_COMMENT from (select from Post where postTitle="Second") to (select from Comment where content="Thirteenth Comment")
create edge HAS_COMMENT from (select from Post where postTitle="Second") to (select from Comment where content="Fourteenth Comment")
要获得所需的结果,您可以使用以下查询:
select expand($ris)
let $a = (select from Post where postTitle = 'First'),
$b = (select from Comment where in('HAS_COMMENT').postTitle in $a.postTitle),
$ris = unionAll($a,$b)
<强>演播室强>:
控制台输出:
----+-----+-------+---------+---------------+---------------+-------+--------------
# |@RID |@CLASS |postTitle|out_HAS_COMMENT|content |someKey|in_HAS_COMMENT
----+-----+-------+---------+---------------+---------------+-------+--------------
0 |#12:0|Post |First |[size=10] |null |null |null
1 |#13:0|Comment|null |null |First Comment |1 |[size=1]
2 |#13:1|Comment|null |null |Second Comment |2 |[size=1]
3 |#13:2|Comment|null |null |Third Comment |3 |[size=1]
4 |#13:3|Comment|null |null |Fourth Comment |4 |[size=1]
5 |#13:4|Comment|null |null |Fifth Comment |5 |[size=1]
6 |#13:5|Comment|null |null |Sixth Comment |6 |[size=1]
7 |#13:6|Comment|null |null |Seventh Comment|7 |[size=1]
8 |#13:7|Comment|null |null |Eighth Comment |8 |[size=1]
9 |#13:8|Comment|null |null |Ninth Comment |9 |[size=1]
10 |#13:9|Comment|null |null |Tenth Comment |10 |[size=1]
----+-----+-------+---------+---------------+---------------+-------+--------------
关于更新下划线的问题,要从@rid
获取完整记录,您可以使用expand()
功能。
示例:
获取与顶点Post相关的所有注释postTitle = 'Second'
查询:select expand(out('HAS_COMMENT')) from Post where postTitle = 'Second'
<强>演播室强>:
控制台输出:
----+------+-------+------------------+-------+--------------
# |@RID |@CLASS |content |someKey|in_HAS_COMMENT
----+------+-------+------------------+-------+--------------
0 |#13:10|Comment|Eleventh Comment |11 |[size=1]
1 |#13:11|Comment|Twelfth Comment |12 |[size=1]
2 |#13:12|Comment|Thirteenth Comment|13 |[size=1]
3 |#13:13|Comment|Fourteenth Comment|14 |[size=1]
----+------+-------+------------------+-------+--------------
希望有所帮助
<强> EDITED 强>
<强>查询强>:
select *, $a as comments from Post
let $a = (select @class, content, someKey from Comment where in('HAS_COMMENT').postTitle in $parent.current.postTitle)
<强>演播室强>: