我认为这是一个非常简单的问题,但无法弄清楚如何做到这一点。我有这两个数组:
(
[0] => Array
(
[accordion_title] => [accordion-title]Title 1[/accordion-title]
)
[1] => Array
(
[accordion_title] => [accordion-title]Title 2[/accordion-title]
)
)
(
[0] => Array
(
[accordion_content] => [accordion-content]Content 1[/accordion-content]
)
[1] => Array
(
[accordion_content] => [accordion-content]Content 2[/accordion-content]
)
)
如何组合/合并它们看起来像这样?
(
[0] => Array
(
[accordion_title] => [accordion-title]Title 1[/accordion-title]
[accordion_content] => [accordion-content]Content 1[/accordion-content]
)
[1] => Array
(
[accordion_title] => [accordion-title]Title 2[/accordion-title]
[accordion_content] => [accordion-content]Content 2[/accordion-content]
)
)
感谢您的帮助。
答案 0 :(得分:2)
您可以尝试这种方式:
$array1 = array( array('accordion_title'=>'Title 1'),array('accordion_title'=>'Title 2') );
$array2 = array( array('accordion_content'=>'Content 1'),array('accordion_content'=>'Content 2') );
$array3 = array();
foreach( $array1 as $key => $array )
{
$array3[] = array( key($array) => current($array), key($array2[$key]) => current($array2[$key]) );
}
print_r( $array3 );
这是输出:
Array
(
[0] => Array
(
[accordion_title] => Title 1
[accordion_content] => Content 1
)
[1] => Array
(
[accordion_title] => Title 2
[accordion_content] => Content 2
)
)
使用此功能,您可以组合无限阵列(不仅仅是两个),即使它们具有不同的大小:
/* Groups passed arrays in an array of associative arrays with same keys and values
*
* @example $array1 = array( array('a'=>'val1'),array('a'=>'val2') );
* $array2 = array( array('b'=>'val3'),array('b'=>'val4') );
* $array3 = array( array('c'=>'val5'),array(),array('c'=>'val6') );
* multiArrayCombine( $array1, $array2, $array3 );
* return: array
* (
* 0 => array('a'=>'val1','b'=>'val3','c'=>'val5'),
* 1 => array('a'=>'val2','b'=>'val4'),
* 2 => array('c'=>'val6')
* )
*
* @param array $array1[, $array2[, $array3...]]
*
* @option const T_OBJECT_CAST cast returned assoc arrays as stdObject
*
* @return array
*/
function multiArrayCombine()
{
/* Get all passed parameters and T_OBJECT_CAST option: */
$args = func_get_args();
$asObject = ( T_OBJECT_CAST == end($args) );
if( $asObject ) array_pop( $args );
$retval = array(); # Init array to be returned
/* Retrieve highest passed arrays key: */
$max = 0;
foreach( $args as $array ) $max = max( $max, max( array_keys($array) ) );
/* Loop for each arrays key: */
for( $i=0; $i<=$max; $i++ )
{
/* Init associative array to add: */
$add = array();
/* Process actual key ($i) of each passed array: */
foreach( $args as $array )
{
/* If the key ($i) exists, add each passed array: */
if( isset($array[$i]) AND is_array($array[$i]) )
{
foreach( $array[$i] as $key => $val )
{ $add[$key] = $val; }
}
}
/* Add the obtained associative array to return array */
if( $asObject ) $retval[] = (object) $add;
else $retval[] = $add;
}
return $retval;
}
所以,使用以下代码(三个数组):
$array1 = array( array('accordion_title'=>'Title 1'),array('accordion_title'=>'Title 2') );
$array2 = array( array('accordion_content'=>'Content 1'),array('accordion_content'=>'Content 2') );
$array3 = array( array('accordion_date'=>'Date 1'),array(),array('accordion_date'=>'Date 3') );
print_r( multiArrayCombine( $array1, $array2, $array3 ) );
输出是:
Array
(
[0] => Array
(
[accordion_title] => Title 1
[accordion_content] => Content 1
[accordion_date] => Date 1
)
[1] => Array
(
[accordion_title] => Title 2
[accordion_content] => Content 2
)
[2] => Array
(
[accordion_date] => Date 3
)
)
的 eval.in demo 强>
T_OBJECT_CAST
:在数组列表后传递常量T_OBJECT_CAST
,返回数组的行格式为stdObjects而不是数组。为了不允许预定的参数,我不将函数格式化为multiArrayCombine( $arg1, $arg2, ... )
,而是使用func_get_args()
函数,“允许用户定义的函数接受可变长度的参数列表”。 / p>
首先(在最新的更新中),我检查最后一个参数是否是预定义常量T_OBJECT_CAST
:如果是,我将$asObject
设置为True
,然后我{ {3}}在arguments数组的末尾;现在在$args
变量中,每个传递的数组都有一个数组。
下一步:我检索所有传递的数组的最大键值;我选择这种方式而不是更舒适foreach( $array1 as $row )
,以避免在其他数组之一的行数多于第一个数据时省略值。 最终不会删除数字键。
然后,主循环:我处理每一行原始数组,并将它们的键和值添加到将添加到返回数组的行。 如果有重复的密钥,则仅返回最后一个密钥。
在处理完每个数组之后,我将获得的行(如果传递了这个选项,则转换为object)添加到返回的数组中。
这就是全部!
在这里结束,对不起
答案 1 :(得分:1)
这样的事情应该有效:
$merged = [];
$array1 = [ ... ];
$array2 = [ ... ];
foreach ($array1 as $key => $value) {
$merged[$key][] = $value;
}
foreach ($array2 as $key => $value) {
$merged[$key][] = $value;
}
我希望我在这里所做的事情是有道理的。
答案 2 :(得分:0)
只需通过 array_merge()
进行迭代 array_map()
调用,然后传入所有应合并的数组。
代码:(Demo)
$array1 = [
['accordion_title' => '[accordion-title]Title 1[/accordion-title]'],
['accordion_title' => '[accordion-title]Title 2[/accordion-title]']
];
$array2 = [
['accordion_content' => '[accordion-content]Content 1[/accordion-content]'],
['accordion_content' => '[accordion-content]Content 2[/accordion-content]']
];
var_export(array_map('array_merge', $array1, $array2));
输出:
array (
0 =>
array (
'accordion_title' => '[accordion-title]Title 1[/accordion-title]',
'accordion_content' => '[accordion-content]Content 1[/accordion-content]',
),
1 =>
array (
'accordion_title' => '[accordion-title]Title 2[/accordion-title]',
'accordion_content' => '[accordion-content]Content 2[/accordion-content]',
),
)
答案 3 :(得分:-1)
也许使用php函数array array_merge($array1 ,$array2)