我一直在获得SQLException，但我怀疑这不是问题所在。 表是：
<FrameLayout
android:id="@+id/frame_test"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:background="?android:selectableItemBackground"
android:clickable="true">
<TextView
android:id="@+id/test"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:background="@drawable/rectangle_empty_white"
android:padding="8dp"
android:text="@string/test"
android:textAllCaps="true"
android:textColor="@color/white"
android:textSize="14sp" />
</FrameLayout>
插入陈述：
create table person (first varchar(30) DEFAULT NULL, last varchar(30) DEFAULT NULL, gender char(1) DEFAULT NULL, age tinyint(4) DEFAULT NULL);
Spark代码：
insert into person values('Barack','Obama','M',54);
insert into person values('Hillary','Clinton','f',34);
错误：
public static void main(String[] args) {
SparkConf conf = new SparkConf().setAppName("Stackoverflow")
.setMaster("local[4]");
JavaSparkContext sc = new JavaSparkContext(conf);
SQLContext sqlContext = new SQLContext(sc);
Map<String, String> options = new HashMap<>();
options.put("url", "jdbc:mariadb://localhost:3306/persondb");
options.put("user", "user");
options.put("password", "password333");
options.put("dbtable", "(select * from person where gender = 'M') as someone");
DataFrame jdbcDF = sqlContext.read().format("jdbc"). options(options).load();
jdbcDF.show();
我尝试更改表格stmt（@jmj）：
Exception in thread "main" org.apache.spark.SparkException: Job aborted due to stage failure: Task 0 in stage 0.0 failed 1 times, most recent failure: Lost task 0.0 in stage 0.0 (TID 0, localhost): java.sql.SQLException: Out of range value for column 'age' : value age is not in Integer range
然后它适用于某些查询，但主要是它给出了：
create table person (first varchar(30) DEFAULT NULL, last varchar(30) DEFAULT NULL, gender char(1) DEFAULT NULL, age int DEFAULT NULL);