Question

我有一个日志文件，我正在尝试编写一个shell脚本来查找多行文件中的多个字符串。

例如，如果我看到短语＆＃34; class = com.comcast.parker.GetCurrentAudioLanguageResponse＆＃34;和＆＃34;状态：好的＆＃34;在日志中，我应该打印getAudioLanguage SUCCESSFUL，否则getAudioLanguage FAILED。所以我的shell脚本是这样的：

脚本文件：

logfile=$1

if grep "{\"class\":\"com.comcast.parker.GetCurrentAudioLanguageResponse\"" jags.txt | grep "{\"status\":\"OK\"" | wc -l ; then
    echo "getAudioLanguage SUCCESSFUL"
fi
if grep "{\"class\":\"com.comcast.parker.GetCurrentAudioLanguageResponse\"" $logfile | grep -q "GENERAL_ERROR" | wc -l ; then
    echo "getAudioLanguage FAILED"
fi

在日志中，我获得状态为GENERAL_ERROR，因此它应该打印FAILED，但输出显示为getAudioLanguage SUCCESSFUL ..

对此有何帮助？

日志文件：

160125-11:11:28.442500 [mod=SYS, lvl=INFO] [tid=2332] ======= Message is onRPCCall ======>
160125-11:11:28.442614 [mod=SYS, lvl=INFO] [tid=2332] Entering onRPCCallEvent for request ---> getAudioLanguage
160125-11:11:28.442845 [mod=SYS, lvl=INFO] [tid=2332] Received json request = {"event":1,"handler":1,"name":"onRPCCall","params":{"callGUID":"d75a5bab-6b29-4ab4-9f7e-3cf32d4a05b1","callParams":[{"getAudioLanguage":{}}],"class":"com.comcast.xre.events.XRERPCCallInfo","destinationSessionGUID":"ab00ebea-5f63-4619-9877-273a2bceea1d","method":"getAudioLanguage","sourceSessionGUID":"ab00ebea-5f63-4619-9877-273a2bceea1d"},"phase":"STANDARD","source":1}

160125-11:11:28.442920 [mod=SYS, lvl=INFO] [tid=2332] GetCurrentAudioLanguage : Entered
160125-11:11:28.442968 [mod=SYS, lvl=INFO] [tid=2332] pMainPlayer is NULL.
160125-11:11:28.443012 [mod=SYS, lvl=INFO] [tid=2332] getAudioLanguage: Get Audio Language returned ��v`>       T�=     T0~�t
160125-11:11:28.443676 [mod=SYS, lvl=INFO] [tid=2332] ====== Response sending is {"appId":1,"command":"CALL","commandIndex":5,"method":"generateAppEvent","params":[{"class":"com.comcast.xre.events.XREOutgoingEvent","name":"onRPCReturn","params":{"callGUID":"d75a5bab-6b29-4ab4-9f7e-3cf32d4a05b1","class":"com.comcast.xre.events.XRERPCReturnInfo","destinationSessionGUID":"ab00ebea-5f63-4619-9877-273a2bceea1d","method":"getAudioLanguage","returnVal":{"class":"com.comcast.parker.GetCurrentAudioLanguageResponse","status":"GENERAL_ERROR","statusMessage":"Getting Current Audio Language was unsuccessful."},"sourceSessionGUID":"ab00ebea-5f63-4619-9877-273a2bceea1d"}},"ab00ebea-5f63-4619-9877-273a2bceea1d"],"targetId":1,"targetPath":"","timestamp":0}

Answer 1

假设您的搜索模式编写正确，那么您可以使用以下内容：

if grep pattern_one file | grep -q pattern_two; then
    echo "getAudioLanguage SUCCESSFUL"
fi

这会过滤第一个模式的输出并使用grep -q，其退出状态指示第二个模式是否也匹配。

那就是说，有点像你试图解析JSON。如果可能的话，最好使用jq之类的东西。

Answer 2

您可以使用单个grep来执行此操作，而不是多个awk：

awk '/{"class":"com\.comcast\.parker\.GetCurrentAudioLanguageResponse"/{
   exit ($0 !~ /"status":"GENERAL_ERROR"/)}' file && echo "getAudioLanguage FAILED"

awk '/{"class":"com\.comcast\.parker\.GetCurrentAudioLanguageResponse"/{
   exit ($0 !~ /"status":"OK"/)}' file && echo "getAudioLanguage SUCCESSFUL"

在shell scipt上需要一些帮助（使用grep命令）

2 个答案: