Question

 Application.OpenForms["formname"];

是否有其他方式可以访问打开的表单。我的应用程序虽然已打开但看不到此表单。我不知道为什么。

Answer 1

我建议您先调试代码，检查要加载的Form实际名称是什么：

foreach (Form form in Application.OpenForms) {
    string name = form.Name; //check out this name!!
    //print, or anything else will do, you only want to get the name
    //note that you should be able to get any form as long as you get its name correct
}

然后，一旦您知道代码出了什么问题，只需执行以下操作：

Form form = Application.OpenForms[name]; //use the same name as whatever is available according to your debug

获取form。

要查看有关可能错误的更多信息，请参阅Hans Passant's Post

Answer 2

您必须首先实现for (i = 0; i < N; i += 2) { arr[2 * i + 0] = A[i]; arr[2 * i + 1] = A[i+1]; arr[2 * i + 2] = B[i]; arr[2 * i + 3] = B[i+1]; }。之后你可以访问它：

Form

Answer 3

获取开放表格并不是真正必要的名称。您可以通过索引获得所需的表单：

Form frm = Application.OpenForms[0] //Will get the main form
Form frm = Application.OpenForms[1] //Will get the first child

OpenForms集合中的表单的排序方式与创建它的方式相同

否则，另一种方法是保存对表单的引用，然后通过此引用访问它。

//Where you want to save the reference:
Form theForm;
//Where you create the form:
myClass.theForm = new MyForm();
//Where you want to get that form:
MessageBox.Show(myClass.theForm.Caption);

（myClass是将保留对表单的引用的类，假设您从不同的类访问它）

（另外，看看你是否受此影响：Application.OpenForms.Count = 0 always）

Answer 4

要使用此属性访问表单，您的form必须有Name。

请记住它不是实例名称，也不是形式文本：

  Form1 f1 = new Form1();    //not "f1" is the "Name"  
  f1.Text = "it is title of the form"; //neither "Text" is the "Name"
  f1.Name= "its the name"; //it is the "Name"

样品：

frm_myform form1 = new frm_myform(); 
frm_myform.Name = "form1";

有没有其他方法可以访问C＃中的开放表单？

4 个答案: