我最近一直在使用一些压缩算法但是,在过去的几天里,我在python中实现LZ78时遇到了一些麻烦。我在网上浏览了一些例子,但没有真正找到任何可靠的编码和解码输入。有没有人有我可以查看的资源或我可以检查的代码?
由于
答案 0 :(得分:6)
以下是两者的压缩和解压缩:
def compress(uncompressed):
"""Compress a string to a list of output symbols."""
# Build the dictionary.
dict_size = 256
dictionary = dict((chr(i), chr(i)) for i in xrange(dict_size))
# in Python 3: dictionary = {chr(i): chr(i) for i in range(dict_size)}
w = ""
result = []
for c in uncompressed:
wc = w + c
if wc in dictionary:
w = wc
else:
result.append(dictionary[w])
# Add wc to the dictionary.
dictionary[wc] = dict_size
dict_size += 1
w = c
# Output the code for w.
if w:
result.append(dictionary[w])
return result
def decompress(compressed):
"""Decompress a list of output ks to a string."""
from cStringIO import StringIO
# Build the dictionary.
dict_size = 256
dictionary = dict((chr(i), chr(i)) for i in xrange(dict_size))
# in Python 3: dictionary = {chr(i): chr(i) for i in range(dict_size)}
# use StringIO, otherwise this becomes O(N^2)
# due to string concatenation in a loop
result = StringIO()
w = compressed.pop(0)
result.write(w)
for k in compressed:
if k in dictionary:
entry = dictionary[k]
elif k == dict_size:
entry = w + w[0]
else:
raise ValueError('Bad compressed k: %s' % k)
result.write(entry)
# Add w+entry[0] to the dictionary.
dictionary[dict_size] = w + entry[0]
dict_size += 1
w = entry
return result.getvalue()
# How to use:
compressed = compress('TOBEORNOTTOBEORTOBEORNOT')
print (compressed)
decompressed = decompress(compressed)
print (decompressed)
希望这有帮助