Question

我只是想让一个简单的旋转木马工作，但页面只显示我没有任何旋转木马的图片。我该如何解决？我正在关注“使用入门”指南：http://kenwheeler.github.io/slick/

<html>
  <head>
  <title>My Now Amazing Webpage</title>
  <link rel="stylesheet" type="text/css" href="slick/slick.css"/>
  <link rel="stylesheet" type="text/css" href="slick/slick-theme.css"/>
  </head>
  <body>

  <div class="your-class">
    <div><img src="images/image1.png"></div>
    <div><img src="images/image2.png"></div>
    <div><img src="images/image3.png"></div>
    <div><img src="images/image4.png"></div>
    <div><img src="images/image5.png"></div>
    <div><img src="images/image13.png"></div>
    <div><img src="images/image6.png"></div>
    <div><img src="images/image21.png"></div>
    <div><img src="images/image3.png"></div>
    <div><img src="images/image9.png"></div>
    <div><img src="images/image12.png"></div>
    <div><img src="images/image13.png"></div>
  </div>

  <script type="text/javascript" src="http://code.jquery.com/jquery-1.11.0.min.js"></script>
  <script type="text/javascript" src="http://code.jquery.com/jquery-migrate-1.2.1.min.js"></script>
  <script type="text/javascript" src="slick/slick.min.js"></script>

  <script type="text/javascript">
    $(document).ready(function(){
      $('.your-class').slick({
        setting-name: setting-value
      });
    });
    $('.variable-width').slick({
          dots: true,
          infinite: true,
          speed: 300,
          slidesToShow: 1,
          centerMode: true,
          variableWidth: true
    });
    $('.autoplay').slick({
          slidesToShow: 3,
          slidesToScroll: 1,
          autoplay: true,
          autoplaySpeed: 2000,
    });
  </script>

  </body>
</html>

Answer 1

您实际上并未初始化div。 setting-name : setting-value是伪代码，表示名称和值需要替换。

正确初始化的一个例子是：

$(document).ready(function(){
    $('.your-class').slick({
      dots: true,
      infinite: true,
      speed: 300,
      slidesToShow: 1,
      centerMode: true,
      variableWidth: true
    });
});

Working Fiddle

我不能得到基本的Slick旋转木马吗？

1 个答案: