我可以使用scrapy来获取所有图像链接。
答案 0 :(得分:1)
是的,你可以。打开HTML(源代码),你看到了
imgAr1[0] = "slides/01.jpg";
imgAr1[1] = "slides/los-altos-remodel.jpg";
imgAr1[2] = "slides/los-altos-remodeling.jpg";
imgAr1[3] = "slides/los-altos-home-remodeling.jpg";
imgAr1[4] = "slides/home-remodel-los-altos.jpg";
imgAr1[5] = "slides/remodel-los-altos.jpg";
imgAr1[6] = "slides/los-altos-remodeling-contractors.jpg";
imgAr1[7] = "slides/remodeling-los-altos.jpg";
imgAr1[8] = "slides/los-altos-home-remodel.jpg";
imgAr1[9] = "slides/home-remodeling-los-altos.jpg";
使用正则表达式,您将获得所有图像的所有链接。