我已经声明了一个字符串,如下所示:
Declare @string
Set @string = 'this line is like this because this is repeated these many times in this line'
我正在尝试找出每个单词重复多少次。我期待像
这样的结果Word Number
this x times
line y times
is z times
依旧......
帮我处理代码。任何帮助,将不胜感激。提前谢谢。
编辑:
到目前为止,我已经找到了替换特定字母的数字。
以下是代码
SELECT Len(@string) - Len(Replace(@string, 'x', '')).
将非常感谢任何解释以及提供的代码。谢谢。
答案 0 :(得分:4)
;WITH splitString(val) AS
(
-- convert the string to xml, seperating the elements by spaces
SELECT CAST('<r><i>' + REPLACE(@string,' ','</i><i>') + '</i></r>' AS XML)
)
SELECT [Key],
COUNT(*) [WordCount]
FROM ( -- select all of the values from the xml created in the cte
SELECT p.value('.','varchar(100)') AS [Key]
FROM splitString
CROSS APPLY val.nodes('//i') t (p)) AS t
GROUP BY [Key]
如果你想获得所有技术......
;WITH splitString(val) AS
(
-- convert the string to xml, seperating the elements by spaces
SELECT CAST('<r><i>' + REPLACE(@string,' ','</i><i>') + '</i></r>' AS XML)
)
SELECT Word,
CAST(COUNT(*) AS VARCHAR)
+ (CASE WHEN COUNT(*) = 1 THEN ' time' ELSE ' times' END) AS Number
FROM ( -- select all of the values from the xml created in the cte
SELECT p.value('.','varchar(100)') AS Word
FROM splitString
CROSS APPLY val.nodes('//i') t (p)) AS t
GROUP BY Word
答案 1 :(得分:2)
使用t-sql拆分器这非常简单。我个人的偏好是Jeff Moden分离器,可以在这里找到。 http://www.sqlservercentral.com/articles/Tally+Table/72993/此处还有其他一些选项。 http://sqlperformance.com/2012/07/t-sql-queries/split-strings
使用Jeff Moden就是这么简单。
Declare @string varchar(1000)
Set @string = 'this line is like this because this is repeated these many times in this line'
select x.Item
, COUNT(*) as WordCount
from dbo.DelimitedSplit8K(@string, ' ') x
group by x.Item
order by x.Item
答案 2 :(得分:1)
以下是可以解决您问题的代码。
首先运行以下功能
CREATE FUNCTION dbo.fnSplit(
@sInputList VARCHAR(8000) -- List of delimited items
, @sDelimiter VARCHAR(8000) = ' ' -- delimiter that separates items
) RETURNS @List TABLE (item VARCHAR(8000))
BEGIN
DECLARE @sItem VARCHAR(8000)
WHILE CHARINDEX(@sDelimiter,@sInputList,0) <> 0
BEGIN
SELECT
@sItem=RTRIM(LTRIM(SUBSTRING(@sInputList,1,CHARINDEX(@sDelimiter,
@sInputList,0)-1))),
@sInputList=RTRIM(LTRIM(SUBSTRING(@sInputList,CHARINDEX(@sDelimiter,
@sInputList,0)+LEN(@sDelimiter),LEN(@sInputList))))
IF LEN(@sItem) > 0
INSERT INTO @List SELECT @sItem
END
IF LEN(@sInputList)> 0
INSERT INTO @List SELECT @sInputList -- Put the last item in
RETURN
END
现在运行此代码
Declare @string Varchar(MAX)
Set @string = 'this line is like this because this is repeated these many times in this line'
DECLARE @Words AS TABLE(
ID INT IDENTITY(1,1),
Words VARCHAR(50))
INSERT INTO @Words
select * from fnSplit(@string, ' ')
SELECT Words AS Word, COUNT(*) Number FROM @Words GROUP BY Words ORDER BY Number DESC