在使用PHPUnit测试一段代码（按照codeigniter mvc编写）时，我收到错误 PHP致命错误：在非对象上调用成员函数getPermissionObject（）。
代码如下所示，产生错误的部分缩进。
class Some_model extends Model
{
var $userid;
var $permisson_object;
var $username;
var $userType;
var $userFirstName;
function Some_model()
{
parent::Model();
$user_obj = @unserialize($this->db_session->userdata('user_object'));
//following line shows error
$this->permisson_object = $user_obj->getPermissionObject();
$this->userid = $user_obj->getUserid();
$this->username = $user_obj->getUsername();
$this->userType =$user_obj->getusertype();
$this->userFirstName = $user_obj->getFirstName()." ".$user_obj->getLastName();
}
}
出现错误是因为测试时我无法从我的测试类生成 $ user_obj （因为它是从会话数据生成的）。
我的要求是在测试类中生成相同的内容，以便我可以使用它。
由于
感谢您的回复。
对象看起来像这样：
User_library Object
(
[username:User_library:private] => staff@some.com
[firstname:User_library:private] => some
[lastname:User_library:private] => Staff
[typename:User_library:private] =>
[userid:User_library:private] => 2
[userType:User_library:private] => 2
[permissionObject:User_library:private] => Permission_library Object
(
[create_custom_attr:Permission_library:private] => 1
[create_jobspecific_attr:Permission_library:private] => 0
[injob:Permission_library:private] => Array
(
[products] => 2
[services] => 2
[options] => 2
[tasks_assigned_to_me] => 2
[tasks_assigned_to_others] => 2
)
[outjob:Permission_library:private] => Array
(
[products] => 2
[services] => 2
[options] => 2
[tasks_assigned_to_others] => 2
)
[samedept:Permission_library:private] => Array
(
)
[alldepts:Permission_library:private] => Array
(
[add_and_assign_tasks] => 4
[add_and_assign_milestones] => 4
)
)
我找不到任何模拟此选项的选项，因为此对象中还包含其他对象。这里User_library Object是类User_library的对象。这里面也有Permission_library对象。我怎样才能通过以下方式模仿上述内容：
$observer = $this->getMock('Some_model', array('Some_model'));
$observer->expects($this->any())
->method('Some_model')
->with($this->equalTo('something'));
我的问题是$this->equalTo('something')中的某些部分会出现什么问题？
答案 0 :(得分：2)
问题的一个可能答案是"Dependency Injection"，坦率地说是我最喜欢的问题。只是简单的嘲笑也是可能的。
一些示例
<?php
// You could pass the session into the object while constructing it
// so in your test you can pass in a "fake" user object (see below)
class Some_model extends Model {
function Some_model($user_object) {
$user_object->yourFunctions();
}
如果这对你不起作用（我不太了解codeigniter），你可以这样做：
<?php
class Some_model extends Model {
function Some_model($user_object=null) {
if($user_obj === null) {
$user_obj = @unserialize($this->db_session->userdata('user_object'));
}
$user_object->yourFunctions();
}
所以在你的测试中你传入一个模拟的用户对象（你为mocking see the docs创建的假实例）并且你的普通代码不需要改变。
同样好的阅读：Slides about PHPUnit best practices from the PHPUnit Author。希望帮助澄清我试图解释的内容：）
假设这是您要测试的代码（缩减为用户ID，因此它更短）
<?php
class Some_model extends Model
{
var $userid;
var $permisson_object;
function Some_model()
{
parent::Model();
$user_obj = @unserialize($this->db_session->userdata('user_object'));
//following line shows error
$this->permisson_object = $user_obj->getPermissionObject();
$this->userid = $user_obj->getUserid();
}
}
使用我试图解释的内容可以构建一个像这样的测试（一个文件中的所有东西都可以复制粘贴，当然会有一个分割它）
class Model { public function Model() {} }
class Some_model extends Model
{
var $userid;
var $permisson_object;
function Some_model($user_obj)
{
parent::Model();
//following line shows error
$this->userid = $user_obj->getUserid();
$this->permisson_object = $user_obj->getPermissionObject();
}
public function getThatUserid() {
// Just to show off how mocking works a little bit better :)
return $this->userid;
}
}
class Permissions {
public function getPermissions() {
// lots of code here maybe
return array("something from" => "the database");
}
}
class User {
public function getUserid() {
// code code
return 1;
}
public function getPermissionObject() {
}
}
class Some_modelTest extends PHPUnit_Framework_Testcase {
public function testConstruction() {
$mockUser = $this->getMock("User");
$mockPermissions = $this->getMock("Permission");
$mockUser->expects($this->once())
->method("getUserid")
->will($this->returnValue(100));
# $mockPermissions->expects($this->once())
# ->method("getPermissions");
// Now for the "magic"
$mockUser->expects($this->once())
->method("getPermissionObject")
->will($this->returnValue($mockPermissions));
// ^^ now we are all set and user_obj is independen of the permissons object
// Now pass the "Fake" user into the model
$model = new Some_model($mockUser);
// and just to show off the "will return value stuff"
$this->assertSame(100, $model->getThatUserid());
}
}
phpunit Some_modelTest.php PHPUnit 3.4.15 by Sebastian Bergmann。
时间：0秒，内存：4.25Mb
好（1次测试，3次断言）
我真的希望有所帮助。这是很多代码，但作为演示它应该适合你。