我相信我正在寻找的解决方案非常简单，但我花了将近一天时间寻找它并没有成功，所以我投降了。
我想将所有请求从package mor;
import java.util.Scanner;
public class Mor {
public static void main(String[] args)
{
Scanner input = new Scanner(System.in);
System.out.println("Type 1 for text to morse, 0 from morse to text.");
String myChoice = input.nextLine();
System.out.println("Type what you want to decode/encode ");
String userMessage = input.nextLine();
System.out.println("");
if("1".equals(myChoice)){
System.out.println(toMorse(userMessage));}
else{
System.out.println(fromMorse(userMessage));
}
}
public static String fromMorse(String userMessage)
{
String s = userMessage;
System.out.printf("Message: %s\n", s);
// string with decoded message
String message = "";
// sample alphabet string
String alphabet = "abcdefghijklmnopqrstuvwxyz";
String[] morseAlphabet = {".-", "-...", "-.-.", "-..", ".", "..-.", "--.", "....",
"..", ".---", "-.-", ".-..", "--", "-.", "---", ".--.", "--.-", ".-.", "...", "-", "..-",
"...-", ".--", "-..-", "-.--", "--.."};
// separate on string letters
String[] letters = s.split(" ");
// iteration morse letters
for (String morseAlph : letters)
{
char alphabetLetter = '?';
int index = -1;
for (int i = 0; i < morseAlphabet.length; i++)
{
if (morseAlphabet[i].equals(morseAlph))
index = i;
}
if (index >= 0) // letter found
alphabetLetter = alphabet.charAt(index);
message += alphabetLetter;
}
return message;
}
public static String toMorse(String userMessage)
{
String s = userMessage;
System.out.printf("Message: %s\n", s);
String message = "";
String alphabet = "abcdefghijklmnopqrstuvwxyz";
String[] morseAlphabet = {".-", "-...", "-.-.", "-..", ".", "..-.", "--.", "....",
"..", ".---", "-.-", ".-..", "--", "-.", "---", ".--.", "--.-", ".-.", "...", "-", "..-",
"...-", ".--", "-..-", "-.--", "--.."};
for (char alphabetLetter : message.toCharArray())
{
int index = -1;
String letter = " ";
for (int i = 0; i < alphabet.length(); i++)
{
if (alphabet.charAt(i) == alphabetLetter)
{
index = i;
}
}
if (index >=0)
{
letter = morseAlphabet[index];
}
message += letter + " ";
}
System.out.printf("Message: %s\n", message);
return message;
}
}
重定向到portail.domain.com文件，将所有其他请求（从我的其他子域）重定向到portail-index.php文件。
这是我的index.php文件：
.htaccess以下是我尝试访问# ROUTING portail SUBDOMAIN TO portail-index.php
RewriteCond %{HTTP_HOST} ^portail.*
RewriteCond %{REQUEST_FILENAME} !-f [OR]
RewriteCond %{REQUEST_URI} ^portail-index.php$
RewriteCond %{REQUEST_FILENAME} !-d [OR]
RewriteCond %{REQUEST_URI} ^/$
RewriteRule .* /portail-index.php [NC,L,QSA]
# REROUTING EVERYTHING ELSE TO index.php
RewriteCond %{REQUEST_FILENAME} !-f
RewriteCond %{REQUEST_FILENAME} !-d [OR]
RewriteCond %{REQUEST_URI} ^/$
RewriteRule .* /index.php [NC,L,QSA]
时的日志结果：
portail.domain.com现在我完全理解导致 applying pattern '.*' to uri ''
RewriteCond: input='portail.domain.com' pattern='^portail.*' => matched
RewriteCond: input='/home/ubuntu/app/preprod/' pattern='!-f' => matched
RewriteCond: input='/home/ubuntu/app/preprod/' pattern='!-d' => not-matched
RewriteCond: input='/' pattern='^/$' => matched
rewrite '' -> '/portail-index.php'
trying to replace prefix /home/ubuntu/domain/app/preprod/ with /
internal redirect with /portail-index.php [INTERNAL REDIRECT]
strip per-dir prefix: /home/ubuntu/domain/app/preprod/index.php -> index.php
applying pattern '.*' to uri 'index.php'
RewriteCond: input='portail.domain.com' pattern='^portail.*' => matched
RewriteCond: input='/home/ubuntu/domain/app/preprod/index.php' pattern='!-f' => not-matched
RewriteCond: input='/index.php' pattern='^portail-index.php$' => not-matched
strip per-dir prefix: /home/ubuntu/domain/app/preprod/index.php -> index.php
applying pattern '.*' to uri 'index.php'
RewriteCond: input='/home/ubuntu/domain/app/preprod/index.php' pattern='!-f' => not-matched
pass through /home/ubuntu/domain/app/preprod/index.php
重放一大堆重写规则。 我不明白为什么第二次传递再次与internal redirect规则不符。
我尝试用portail.domain.com标志替换L标志，但无济于事。结果完全一样。我还尝试了几种重写规则的改编，但这些尝试都没有奏效。我花了几个小时阅读Apache rewrite_mod文档，所以我相信我对模块的理解非常好，但是在这种情况下无法使它正常工作。
任何关于它为什么不起作用或更好的建议：如何使这项工作受到欢迎。
---编辑---
非常感谢你的帮助@Anubhava。以下是我实现END文件版本后得到的日志：
.htaccess这会带你到任何地方吗？
---第二次编辑---
strip per-dir prefix: /home/ubuntu/domain/app/preprod/ ->
applying pattern '^' to uri ''
RewriteCond: input='/home/ubuntu/domain/app/preprod/' pattern='-f' => not-matched
RewriteCond: input='/home/ubuntu/domain/app/preprod/' pattern='-d' => matched
pass through /home/ubuntu/domain/app/preprod/
strip per-dir prefix: /home/ubuntu/domain/app/preprod/index.php -> index.php
applying pattern '^' to uri 'index.php'
RewriteCond: input='/home/ubuntu/domain/app/preprod/index.php' pattern='-f' => matched
pass through /home/ubuntu/domain/app/preprod/index.php
我真的不明白为什么调用strip per-dir prefix: /home/ubuntu/domain/app/preprod/ ->
applying pattern '^' to uri ''
RewriteCond: input='/home/ubuntu/domain/app/preprod/' pattern='-f' => not-matched
RewriteCond: input='/home/ubuntu/domain/app/preprod/' pattern='-d' => matched
pass through /home/ubuntu/domain/app/preprod/
strip per-dir prefix: /home/ubuntu/domain/app/preprod/index.php -> index.php
applying pattern '^' to uri 'index.php'
RewriteCond: input='/home/ubuntu/domain/app/preprod/index.php' pattern='-f' => matched
pass through /home/ubuntu/domain/app/preprod/index.php
不会导致portail.domain.com。
答案 0 :(得分：1)
你有一些多余的条件。你有这样的规则：
# ROUTING portail SUBDOMAIN TO portail-index.php
RewriteCond %{HTTP_HOST} ^portail\. [NC]
RewriteRule ^(index\.)?[^.]*$ portail-index.php [L,NC]
RewriteCond %{REQUEST_FILENAME} -f [OR]
RewriteCond %{REQUEST_FILENAME} -d
RewriteRule ^ - [L]
# REROUTING EVERYTHING ELSE TO index.php
RewriteCond %{HTTP_HOST} !^portail\. [NC]
RewriteRule ^ index.php [L]