下面是示例代码,其中我将所有表名存储在一个表(table_config)中,并尝试将每个表的一条记录插入其临时表中,并尝试获取特定的rowid以进一步需要。
所以我需要每个表格行类型来完成这项工作,这是动态的。你能帮帮我吗?
DECLARE
l_row table_name%ROWTYPE;
l_rowid ROWID;
l_table_name all_tab_partitions.table_name%TYPE;
l_temp_table_name all_tab_partitions.table_name%TYPE;
BEGIN
FOR tab IN
(select table_name from
Table_config)
LOOP
l_table_name:= tab.table_name;
l_temp_table_name:= 'TEMP_'||l_table_name;
SELECT * INTO l_row
FROM l_table_name
WHERE ROWNUM=1;
INSERT INTO l_temp_table_name VALUES l_row
RETURNING ROWID INTO l_rowid;
COMMIT;
END LOOP;
END;
谢谢你, 普拉迪普
答案 0 :(得分:0)
你不能像上面的OldProgrammer在评论中提到的那样做。
您必须使用动态SQL来实现您想要实现的目标。
DECLARE
temp_table VARCHAR2(255);
source_table VARCHAR2(255);
sql_stmt VARCHAR2(255);
CURSOR c1 IS
SELECT table_name FROM user_Tables;
BEGIN
FOR c1_Rec IN c1 LOOP
temp_table := 'TEMP_'||c1_rec.table_name;
source_table := c1_rec.table_name;
sql_stmt := 'INSERT INTO '||temp_table||' SELECT * FROM '||source_table||' WHERE rownum = 1';
EXECUTE IMMEDIATE sql_stmt;
END LOOP;
END;
/
答案 1 :(得分:0)
没有为您编写完整的答案。 你为什么不做这样的事?
DrawerLayout
答案 2 :(得分:0)
以下是解决方案。你需要这个rowid?没有它我会更简单,因为你不能使用insert作为select
返回DECLARE
l_rowid ROWID;
l_table_name all_tab_partitions.table_name%TYPE;
l_temp_table_name all_tab_partitions.table_name%TYPE;
v_sql1 varchar2(4000);
v_sql2 varchar2(4000);
BEGIN
FOR tab IN (select table_name from Table_config) LOOP
l_table_name:= tab.table_name;
l_temp_table_name:= 'TEMP_'||l_table_name;
v_sql1 := 'select rowid from ' || l_table_name || ' where rownum =1 for update';
v_sql2 := 'insert into ' || l_temp_table_name || ' select * from ' || l_table_name || ' where rownum = 1';
execute immediate v_sql1 into l_rowid;
execute immediate v_sql2;
commit;
END LOOP;
END;
/
答案 3 :(得分:0)
您应该调查EXECUTE IMMEDIATE INTO
。我认为,当与上面的一些动态SQL示例结合使用时,这将是获得ROWID
的绝佳方法。这是一个例子:
DECLARE
DYN_SQL VARCHAR(4000) := 'SELECT 1 FROM DUAL';
INTO_VAR NUMBER(1);
BEGIN
EXECUTE IMMEDIATE DYN_SQL INTO INTO_VAR;
DBMS_OUTPUT.PUT_LINE(INTO_VAR);
END;
答案 4 :(得分:0)
谢谢大家的回复。实际上我试图在间隔分区表上实现分区交换。我现在使用Dynamic Sql实现了它。最初我试图通过使用rowid来实现它,当我对一个表进行硬编码时这是正常的,但是当我想要配置它并将它用于多个表时,我被卡在那个%ROWTYPE上。
在下面的代码中,我在几个地方都有硬编码的表名,可以修改为动态,但问题是如何为我们传递的每个表获取%ROWTYPE。
DECLARE
l_table_name table_config.table_name%TYPE;
l_query_temp VARCHAR2(1000);
l_part_table_name all_tab_partitions.table_name%TYPE;
l_part_name all_tab_partitions.partition_name%TYPE;
l_temp_table_name all_tab_partitions.table_name%TYPE;
l_row test_archival%ROWTYPE;
l_rowid ROWID;
l_arch_table_name all_tab_partitions.table_name%TYPE;
l_arch_part_name VARCHAR2(30);
l_query_arch VARCHAR2(1000);
l_query_source VARCHAR2(1000);
BEGIN
<<outer_loop>>
FOR tab IN
(SELECT table_name FROM
table_config)
LOOP
l_table_name:= tab.table_name;
<<inner_loop>>
FOR part IN
(SELECT table_name, partition_position, partition_name FROM
(SELECT table_name, partition_position, partition_name,
DENSE_RANK() OVER (PARTITION BY table_name ORDER BY partition_position DESC) AS RANK
FROM all_tab_partitions
WHERE table_name=l_table_name
) WHERE RANK NOT IN(1, 2) ORDER BY partition_position)
LOOP
l_part_table_name:= part.table_name;
l_part_name:= part.partition_name;
l_temp_table_name := 'TEMP_'||l_part_table_name;
l_arch_table_name := 'ARCH_'||l_part_table_name;
l_query_temp := 'ALTER TABLE '
|| l_part_table_name
|| ' EXCHANGE PARTITION '
|| l_part_name
|| ' WITH TABLE '
|| l_temp_table_name
||' INCLUDING INDEXES WITHOUT VALIDATION';
EXECUTE IMMEDIATE l_query_temp;
COMMIT;
SELECT * INTO l_row FROM temp_test_archival WHERE ROWNUM = 1;
INSERT INTO arch_test_archival VALUES l_row RETURNING ROWID INTO l_rowid;
COMMIT;
SELECT subobject_name
INTO l_arch_part_name FROM user_objects
WHERE data_object_id = dbms_rowid.rowid_object(l_rowid);
DELETE from arch_test_archival where rowid=l_rowid;
COMMIT;
l_query_arch := 'ALTER TABLE '
||'ARCH_TEST_ARCHIVAL'
||' EXCHANGE PARTITION '
||l_arch_part_name
||' WITH TABLE '
||'TEMP_TEST_ARCHIVAL'
||' INCLUDING INDEXES WITHOUT VALIDATION';
EXECUTE IMMEDIATE l_query_arch;
END LOOP;
END LOOP;
END;
/