Question

所以我在android地图中使用下面的代码在我的绘图方法中绘制这个三角形：

paint.setARGB(255, 153, 29, 29);
paint.setStyle(Paint.Style.FILL_AND_STROKE);
paint.setAntiAlias(true);

Path path = new Path();
path.moveTo(point1_returned.x, point1_returned.y);
path.lineTo(point2_returned.x, point2_returned.y);
path.moveTo(point2_returned.x, point2_returned.y);
path.lineTo(point3_returned.x, point3_returned.y);
path.moveTo(point3_returned.x, point3_returned.y);
path.lineTo(point1_returned.x, point1_returned.y);
path.close();

canvas.drawPath(path, paint);

pointX_returned是我从字段中获得的坐标。它们基本上是纬度和经度。结果是一个漂亮的三角形，但内部人员是空的，因此我可以看到地图。有办法以某种方式填补它吗？

Answer 1

好的我已经完成了。我正在分享这段代码以防其他人需要它：

super.draw(canvas, mapView, true);

Paint paint = new Paint(Paint.ANTI_ALIAS_FLAG);

paint.setStrokeWidth(2);
paint.setColor(android.graphics.Color.RED);     
paint.setStyle(Paint.Style.FILL_AND_STROKE);
paint.setAntiAlias(true);

Point point1_draw = new Point();        
Point point2_draw = new Point();    
Point point3_draw = new Point();

mapView.getProjection().toPixels(point1, point1_draw);
mapView.getProjection().toPixels(point2, point2_draw);
mapView.getProjection().toPixels(point3, point3_draw);

Path path = new Path();
path.setFillType(Path.FillType.EVEN_ODD);
path.moveTo(point1_draw.x,point1_draw.y);
path.lineTo(point2_draw.x,point2_draw.y);
path.lineTo(point3_draw.x,point3_draw.y);
path.lineTo(point1_draw.x,point1_draw.y);
path.close();

canvas.drawPath(path, paint);

//canvas.drawLine(point1_draw.x,point1_draw.y,point2_draw.x,point2_draw.y, paint);

return true;

感谢尼古拉斯的暗示！

Answer 2

您可能需要执行以下操作：

Paint red = new Paint();

red.setColor(android.graphics.Color.RED);
red.setStyle(Paint.Style.FILL);

并将此颜色用于您的路径，而不是您的ARGB。确保路径的最后一点在第一点结束，这也是有道理的。

告诉我它是否有效！

Answer 3

你也可以使用vertice：

private static final int verticesColors[] = {
    Color.LTGRAY, Color.LTGRAY, Color.LTGRAY, 0xFF000000, 0xFF000000, 0xFF000000
};
float verts[] = {
    point1.x, point1.y, point2.x, point2.y, point3.x, point3.y
};
canvas.drawVertices(Canvas.VertexMode.TRIANGLES, verts.length, verts, 0, null, 0, verticesColors,   0, null, 0, 0, new Paint());

Answer 4

此函数显示如何从位图创建三角形。也就是说，创建三角形裁剪图像。请尝试以下代码或download demo example

 public static Bitmap getTriangleBitmap(Bitmap bitmap, int radius) {
        Bitmap finalBitmap;
        if (bitmap.getWidth() != radius || bitmap.getHeight() != radius)
            finalBitmap = Bitmap.createScaledBitmap(bitmap, radius, radius,
                    false);
        else
            finalBitmap = bitmap;
        Bitmap output = Bitmap.createBitmap(finalBitmap.getWidth(),
                finalBitmap.getHeight(), Bitmap.Config.ARGB_8888);
        Canvas canvas = new Canvas(output);

        Paint paint = new Paint();
        final Rect rect = new Rect(0, 0, finalBitmap.getWidth(),
                finalBitmap.getHeight());

        Point point1_draw = new Point(75, 0);
        Point point2_draw = new Point(0, 180);
        Point point3_draw = new Point(180, 180);

        Path path = new Path();
        path.moveTo(point1_draw.x, point1_draw.y);
        path.lineTo(point2_draw.x, point2_draw.y);
        path.lineTo(point3_draw.x, point3_draw.y);
        path.lineTo(point1_draw.x, point1_draw.y);
        path.close();
        canvas.drawARGB(0, 0, 0, 0);
        paint.setColor(Color.parseColor("#BAB399"));
        canvas.drawPath(path, paint);
        paint.setXfermode(new PorterDuffXfermode(PorterDuff.Mode.SRC_IN));
        canvas.drawBitmap(finalBitmap, rect, rect, paint);

        return output;
    }

上面的函数返回在画布上绘制的三角形图像。 Read more

Answer 5

使用@ Pavel的答案作为指导，如果你没有这些点但是有x，y和高度和宽度，那么这是一个辅助方法。也可以倒置/倒置 - 这对我来说很有用，因为它被用作垂直条形图的结尾。

 private void drawTriangle(int x, int y, int width, int height, boolean inverted, Paint paint, Canvas canvas){

        Point p1 = new Point(x,y);
        int pointX = x + width/2;
        int pointY = inverted?  y + height : y - height;

        Point p2 = new Point(pointX,pointY);
        Point p3 = new Point(x+width,y);


        Path path = new Path();
        path.setFillType(Path.FillType.EVEN_ODD);
        path.moveTo(p1.x,p1.y);
        path.lineTo(p2.x,p2.y);
        path.lineTo(p3.x,p3.y);
        path.close();

        canvas.drawPath(path, paint);
    }

Answer 6

private void drawArrows(Point[] point, Canvas canvas, Paint paint) {

    float [] points  = new float[8];             
    points[0] = point[0].x;      
    points[1] = point[0].y;      
    points[2] = point[1].x;      
    points[3] = point[1].y;         
    points[4] = point[2].x;      
    points[5] = point[2].y;              
    points[6] = point[0].x;      
    points[7] = point[0].y;

    canvas.drawVertices(VertexMode.TRIANGLES, 8, points, 0, null, 0, null, 0, null, 0, 0, paint);
    Path path = new Path();
    path.moveTo(point[0].x , point[0].y);
    path.lineTo(point[1].x,point[1].y);
    path.lineTo(point[2].x,point[2].y);
    canvas.drawPath(path,paint);

}

Answer 7

首次初始化后，您需要删除path.moveTo。

Path path = new Path();
path.moveTo(point1_returned.x, point1_returned.y);
path.lineTo(point2_returned.x, point2_returned.y);
path.lineTo(point3_returned.x, point3_returned.y);
path.lineTo(point1_returned.x, point1_returned.y);
path.close();

Answer 8

在每个InitializeComponent

之后不要moveTo()

换句话说，删除除第一个之外的每个lineTo()。

说真的，如果我只是复制粘贴OP的代码并删除不必要的moveTo()来电，那就可以了。

没有其他事情需要做。

编辑：我知道OP已经发布了他的“最终工作解决方案”，但他没有声明为什么它的工作原理。实际的原因让我非常惊讶，所以我觉得有必要添加一个答案。

如何在Android画布中绘制一个填充三角形？

8 个答案: