Question

我想获得给定年份的以下格式的日期列表;

array:4 [▼
  "04" => "25 Jan 2016 - 31 Jan 2016"
  "03" => "18 Jan 2016 - 24 Jan 2016"
  "02" => "11 Jan 2016 - 17 Jan 2016"
  "01" => "4 Jan 2016 - 10 Jan 2016"
]

数组键显示周数。数组值显示日期。

如果给出的年份等于当前年份，那么我只希望它显示截至本周的日期。

我怎样才能做到这一点？

Answer 1

此用户定义的getDates()函数以周数和年份作为输入将返回所需的结果。

<?php

echo "<pre>";
print_r(getDates('4', '2016'));
echo "</pre>";


function getDates($weekNumber, $year) {
    $returnArr = array();

    for($i=$weekNumber; $i >= 1; $i--) {
        $wno = $i<=9 ? "0".$i : $i;

        $calStr = $year . "W" . $wno;

        $startDate = date('d M Y',strtotime($calStr));

        $endDate = date('d M Y', strtotime($startDate. ' + 6 day'));

        $weekDays = $startDate . ' - ' . $endDate;

        $returnArr[$wno] = $weekDays;
    }

    return $returnArr;
}

<强>输出

Array
(
    [04] => 25 Jan 2016 - 31 Jan 2016
    [03] => 18 Jan 2016 - 24 Jan 2016
    [02] => 11 Jan 2016 - 17 Jan 2016
    [01] => 04 Jan 2016 - 10 Jan 2016
)

PHP获取Mon - Sun日期列表

1 个答案: