Question

这是我的计时器

     private void timer_tick(object sender, EventArgs e)
    {
        string timeNow = "";

        timeNow = DateTime.Now.ToString("hh:mm") + " " + DateTime.Now.ToString("tt");
       medicineAlarm();
    }
    private void medicineAlarm()
    {
        DataTable dt = new DataTable();
        dt = database.getSchedule();

        string AMTime;
        string PMTime;
        string NNTime;
        foreach (DataRow row in dt.Rows)
        {
            AMTime = row["AMIntake"].ToString();
            PMTime = row["PMIntake"].ToString();
            NNTime = row["NNIntake"].ToString();

             if (AMTime == timeNow || PMTime == timeNow || NNTime == timeNow)
            {
                MessageBox.Show("Drink Medicine");
            }
        }
    }

即使我正在运行程序，如何显示消息？希望您能够帮助我。这是我的form_load

    private void Form1_Load(object sender, EventArgs e)
    {
        timer.Interval = 1000;
        timer.Tick += new EventHandler(this.timer_tick);
        timer.Start();

Answer 1

我认为您的代码完全没有编译，因为变量string timeNow = "";是在事件处理程序中声明的，并且在您的方法体中不存在。您可能希望将其传递给类似

的方法

private void medicineAlarm(string timeNow)
{

然后你叫它

 private void timer_tick(object sender, EventArgs e)
{
    string timeNow = "";

    timeNow = DateTime.Now.ToString("hh:mm") + " " + DateTime.Now.ToString("tt");
   medicineAlarm(timeNow);
}

Answer 2

medicineAlarm()方法无法访问您在timeNow事件处理程序中设置的timer_tick()变量。我建议你把变量传递给：

private void timer_tick(object sender, EventArgs e)
{
    string timeNow = DateTime.Now.ToString("hh:mm") + " " + DateTime.Now.ToString("tt");
   medicineAlarm(timeNow);
}

private void medicineAlarm(string timeNow)
{
    DataTable dt = database.getSchedule();

    foreach (DataRow row in dt.Rows)
    {
        foreach(var label in new [] {"AM", "PM", "NN"})
            if (row[label + "Intake"].ToString() == timeNow)
                {
                   MessageBox.Show("Drink Medicine");
                   return;
                }
    }
}

在不同的时间显示

2 个答案: