我是python的绿色。我想在这里创建一个应用程序是我的所有代码。如果数据匹配成功，应用程序将工作，然后它将显示另一个窗口。
from PyQt4.QtCore import SIGNAL
from PyQt4.QtGui import QDialog, QApplication, QPushButton, QLineEdit, QFormLayout
from PyQt4 import QtCore, QtGui
import sys
import os
import MySQLdb as mdb
class Form(QDialog):
def __init__(self, parent=None):
super(Form, self).__init__(parent)
self.le = QLineEdit()
self.le.setObjectName("host")
self.le.setText("Host")
self.pb = QPushButton()
self.pb.setObjectName("connect")
self.pb.setText("Connect")
layout = QFormLayout()
layout.addWidget(self.le)
layout.addWidget(self.pb)
self.setLayout(layout)
self.connect(self.pb, SIGNAL("clicked()"),self.button_click)
self.setWindowTitle("Learning")
def button_click(self):
# shost is a QString object
shost = self.le.text()
if shost:
s_h = "127.0.0.1"
s_n = "root"
s_p = ""
s_d = "code"
s_cn = mdb.connect(s_h, s_n, s_p, s_d)
cursor = s_cn.cursor()
query = "SELECT * FROM `ac` WHERE `acc` = %s "
re = cursor.execute(query,(shost,))
if re:
ex = Example()
ex.show()
else:
print "no"
class Example(QtGui.QWidget):
def __init__(self):
super(Example, self).__init__()
self.initUI()
def run(self):
os.startfile("hyt.exe")
def initUI(self):
QtGui.QToolTip.setFont(QtGui.QFont('SansSerif', 10))
self.setToolTip('This is a <b>QWidget</b> widget')
btn1 = QtGui.QPushButton('Start', self)
btn1.resize(btn1.sizeHint())
btn1.move(20, 20)
btn1.clicked.connect(self.run)
qbtn = QtGui.QPushButton('Quit', self)
qbtn.clicked.connect(QtCore.QCoreApplication.instance().quit)
qbtn.resize(qbtn.sizeHint())
qbtn.move(150, 20)
self.setGeometry(300, 300, 250, 150)
self.setWindowTitle('Python Script')
app = QApplication(sys.argv)
form = Form()
form.show()
app.exec_()
但我的问题是，当我按下按钮然后它将显示Example（）窗口。但是在这里，当我按下按钮然后它显示窗口1秒钟，所以我该如何解决它？
if re:
ex = Example()
ex.show()
else:
print "no"