Question

我从数据库中提取行以查找特定列。现在它拉了5行，我需要为模型中的每一行引用正确的列。这是我的控制器：

public ActionResult Index()
    {
        //Use mimetype as key to find correct rows
        var mimetype = "mcv";
        dynamic LookupData = GetVideoUrls(mimetype);
        return View(LookupData);
    }

    private dynamic GetVideoUrls(string mimetype)
    {
        var VideoService = new AppServices.Video.GetAllVideoByMimeType();
        dynamic videoFiles = VideoService.Execute(mimetype);//Execute grabs the rows from the database
        return (videoFiles);
    }

在我看来，我有：

@model IEnumerable<dynamic>

VideoFiles返回包含13列的五行。我需要为视图中的五行中的每一行访问2列。我该怎么做？

更新这是我的模特：

public class LoginVideoModel
{
    public LoginVideoModel(string englishurl, string spanishurl)
    {
        EnglishVideoUrl = englishurl;
        SpanishVideoUrl = spanishurl;
    }
    public string EnglishVideoUrl
    {
        get;
        set;
    }
    public string SpanishVideoUrl
    {
        get;
        set;
    }
}
public class WelcomeVideoModel
{
    public WelcomeVideoModel(string englishurl, string spanishurl)
    {
        EnglishVideoUrl = englishurl;
        SpanishVideoUrl = spanishurl;
    }
    public string EnglishVideoUrl
    {
        get;
        set;
    }
    public string SpanishVideoUrl
    {
        get;
        set;
    }
}
public class BenefitVideoModel
{
    public BenefitVideoModel(string englishurl, string spanishurl)
    {
        EnglishVideoUrl = englishurl;
        SpanishVideoUrl = spanishurl;
    }
    public string EnglishVideoUrl
    {
        get;
        set;
    }
    public string SpanishVideoUrl
    {
        get;
        set;
    }
}
public class MyEnrollmentVideoModel
{
    public MyEnrollmentVideoModel(string englishurl, string spanishurl)
    {
        EnglishVideoUrl = englishurl;
        SpanishVideoUrl = spanishurl;
    }
    public string EnglishVideoUrl
    {
        get;
        set;
    }
    public string SpanishVideoUrl
    {
        get;
        set;
    }
}
public class AdminSideVideoModel
{
    public AdminSideVideoModel(string englishurl, string spanishurl)
    {
        EnglishVideoUrl = englishurl;
        SpanishVideoUrl = spanishurl;
    }
    public string EnglishVideoUrl
    {
        get;
        set;
    }
    public string SpanishVideoUrl
    {
        get;
        set;
    }
}

希望这也有帮助。

更新这是videoservice.execute代码：

public class GetAllVideoByMimeType
{
    public dynamic Execute(string mimetype)
    {
        return DBRepository.GetAllByCritera<DataContainers.File>("WHERE MimeType = @0", mimetype);
    }
}

更新3 这是存储库：

/// <summary>
    /// Obtain one or more items from db based on Where Clase
    /// </summary>
    /// <typeparam name="T">Table Type</typeparam>
    /// <param name="whereClause">Standard WHERE clause with paramterized statements 
    /// Example: WHERE someID=@0",args: 4
    /// </param>
    /// <param name="arguments"></param>
    /// <returns></returns>
    public static IEnumerable<dynamic> GetAllByCritera<T>(string whereClause, params object[] arguments)
    {
        var model = new DBTableModel<T>();
        return model.All(where: whereClause, args: arguments);

    }

如果我尝试了这个怎么办：

public ActionResult Index()
    {
        //Use mimetype as key to find correct rows
        var mimetype = "mcv";
        dynamic LookupData = GetVideoUrls(mimetype);
        return View(LookupData);
    }

    private dynamic GetVideoUrls(string mimetype)
    {
        var VideoService = new AppServices.Video.GetAllVideoByMimeType();
        List<dynamic> videoFiles = VideoService.Execute(mimetype);
        ApplicationVideoModel appvids = new ApplicationVideoModel();
        dynamic LoginFiles = videoFiles.Where(v => v.OriginalFileNameWithoutExtension == "LoginController").FirstOrDefault();
        dynamic WelcomeFiles = videoFiles.Where(v => v.OriginalFileNameWithoutExtension == "WelcomeController").FirstOrDefault();
        dynamic BenefitFiles = videoFiles.Where(v => v.OriginalFileNameWithoutExtension == "BenefitController").FirstOrDefault();
        dynamic MyEnrollmentFiles = videoFiles.Where(v => v.OriginalFileNameWithoutExtension == "MyEnrollmentController").FirstOrDefault();
        dynamic AdminFiles = videoFiles.Where(v => v.OriginalFileNameWithoutExtension == "AdminSideController").FirstOrDefault();

        return LoginFiles;
    }

每个动态都返回我需要的行，但是如何将每个动态发送到视图？

Answer 1

根据您提供的示例模型，您的常见模型对象可能如下所示

public class VideoUrlModel {    
    public string EnglishVideoUrl { get; set; }
    public string SpanishVideoUrl { get; set; }
}

然后可以按如下方式更新GetVideoUrls

private IEnumrable<VideoUrlModel> GetVideoUrls(string mimetype) {
    var VideoService = new AppServices.Video.GetAllVideoByMimeType();
    var videoFiles = VideoService.Execute(mimetype); 
    var models = videoFiles.Select(row => 
                       new VideoUrlModel { 
                              EnglishVideoUrl = row.englishvideourl,
                              SpanishVideoUrl = row.spanishvideourl
                       });
    return models;
}

由于VideoService.Execute返回IEnumerable<dynamic>，您可以使用 LINQ Select扩展名迭代行，并根据需要创建模型项。

所以现在在你的控制器中可以将集合作为模型传递给视图

public ActionResult Index() {
    //Use mimetype as key to find correct rows
    var mimetype = "mcv";
    var LookupData = GetVideoUrls(mimetype);
    return View(LookupData);
}

您的视图会将模型视为，

@model IEnumerable<VideoUrlModel>

并且可以访问作为视图模型传递的集合

Answer 2

这对我的申请有用：

public ActionResult Index()
    {
        //Use mimetype as key to find correct rows
        var mimetype = "mcv";
        var VideoService = new AppServices.Video.GetAllVideoByMimeType();
        List<dynamic> videoFiles = VideoService.Execute(mimetype);
        dynamic mymodel = new System.Dynamic.ExpandoObject();
        mymodel.LoginFiles = videoFiles.Where(v => v.OriginalFileNameWithoutExtension == "LoginController").FirstOrDefault();
        mymodel.BenefitFiles = videoFiles.Where(v => v.OriginalFileNameWithoutExtension == "BenefitController").FirstOrDefault();
        mymodel.WelcomeFiles = videoFiles.Where(v => v.OriginalFileNameWithoutExtension == "WelcomeController").FirstOrDefault();
        mymodel.MyEnrollmentFiles = videoFiles.Where(v => v.OriginalFileNameWithoutExtension == "MyEnrollmentController").FirstOrDefault();
        mymodel.AdminSideFiles = videoFiles.Where(v => v.OriginalFileNameWithoutExtension == "AdminSideController").FirstOrDefault();
        return View(mymodel);
    }

正如您所见，我使用mymodel.构建模型，我可以使用以下方式在视图中访问它：

@Model.LoginFiles.EnglishVideoURL

感谢您的帮助！

如何将mvc 4中的大量动态返回到视图？

2 个答案: