Question

我正在使用此脚本从我的服务表中查找与service_code匹配的ada_code，然后查找将service_code作为ada_code的事务{1}}不在transactions表

中

WITH dentures AS (
SELECT service_code
FROM services
WHERE (ada_code='D5110' OR ada_code='D5120' OR ada_code='D5130' OR ada_code='D5140' OR ada_code='REMAU' OR ada_code='REAML' OR ada_code='REMAK'))

SELECT t.clinic, COUNT(DISTINCT t.tran_num) AS quantity, d.service_code, SUM(t.amount) AS total, p.fiscal_year, p.period_id
FROM transactions t
INNER JOIN dentures d
ON(t.service_code=d.service_code)
CROSS JOIN period p
WHERE (t.time_ran BETWEEN p.period_start AND p.period_end)
AND status='A'
AND impacts='P'
GROUP BY t.clinic, d.service_code, p.fiscal_year, p.period_id

脚本工作原理查找，但我需要分成两个不同的组。 A组（所有服务代码来自D5110，D5120，D5130，D5140）和B组是剩余的。有没有办法从使用那些service_code的服务中查看ada_code并预先将它们预先确定为一组？在A组中的四个ada_code之间，每个大约有10个，我有35个不同的独特位置，它们也需要保持独立。感谢

Answer 1

不是按服务代码分组，而是按照

之类的case语句进行分组

CASE WHEN servicecode IN (group a codes) "Group A"
       ELSE  servicecode --or "Group B", I'm not sure which you want
END

SQL指定组的值？

1 个答案: