Question

每一行包含一个特殊的时间戳，来电号码，接收者号码，呼叫持续时间（以秒为单位）和每分钟收费的分数（以分钟为单位），全部用＆＃34 ;;分隔。该文件包含数千个看起来像这样的调用。我创建了一个列表而不是字典来访问元素，但我不确定如何计算来自相关电话的来电数量

$anyVariable

Answer 1

我的解决方案非常简单：

首先在打开文件时使用with - 它是一个方便的快捷方式，它提供相同的功能，将此功能包装到try ... except。考虑一下：

lines = []
with open("test.txt", "r") as f:
    for line in f.readlines():
        lines.append(line.strip().split(";"))
print(lines)

counters = {}
# you browse through lists and later through numbers inside lists
for line in lines:
    for number in line:
        # very basic way to count occurences
        if number not in counters:
            counters[number] = 1
        else:
            counters[number] += 1
# in this condition you can tell what number of digits you accept
counters = {elem: counters[elem] for elem in counters.keys() if len(elem) > 5}
print(counters)

Answer 2

这应该让你入门

import csv
import collections

Call = collections.namedtuple("Call", "duration rate time")

calls = {}
with open('path/to/file') as infile:
    for time, nofrom, noto, dur, rate in csv.reader(infile):
        calls.get(nofrom, {}).get(noto,[]).append(Call(dur, rate, time))

for nofrom, logs in calls.items():
    for noto, callist in logs.items():
        print(nofrom, "called", noto, len(callist), "times")

python3：计算列表中重复出现的次数

2 个答案: