Question

我在Cassandra中创建了一个表，并希望根据具有timeuuid类型的列的条件选择数据。

CREATE TABLE shahid.stock_ticks(
symbol varchar,
date int,
trade timeuuid,
trade_details text,
PRIMARY KEY (  (symbol, date), trade   )
) WITH CLUSTERING ORDER BY (trade DESC) ;

INSERT INTO shahid.stock_ticks (symbol, date, trade, trade_details) VALUES ('NFLX', 1, now(), 'this is 10' );
INSERT INTO shahid.stock_ticks (symbol, date, trade, trade_details) VALUES ('NFLX', 1, now(), 'this is 2' );
INSERT INTO shahid.stock_ticks (symbol, date, trade, trade_details) VALUES ('NFLX', 1, now(), 'this is 3' );

以上查询已插入记录，一条记录具有值＆＃39; 2045d660-9415-11e5-9742-c53da2f1a8ec＆＃39;在贸易栏目中。

我想选择这样但是它给出了错误

select * from shahid.stock_ticks  where symbol = 'NFLX' and date = 1 and trade < '2045d660-9415-11e5-9742-c53da2f1a8ec';

提供以下错误

InvalidQueryException: Invalid STRING constant (2045d660-9415-11e5-9742-c53da2f1a8ec) for "trade" of type timeuuid

我也尝试过以下查询，但没有运气

select * from shahid.stock_ticks  where symbol = 'NFLX' and date = 1 and trade < maxTimeuuid('2045d660-9415-11e5-9742-c53da2f1a8ec');
select * from shahid.stock_ticks  where symbol = 'NFLX' and date = 1 and trade < dateOf('2045d660-9415-11e5-9742-c53da2f1a8ec');
select * from shahid.stock_ticks  where symbol = 'NFLX' and date = 1 and trade < unixTimestampOf('2045d660-9415-11e5-9742-c53da2f1a8ec');

Answer 1

删除UUID周围的引号。 Cassandra本身就支持他们，而不是通过Strings。

select * from shahid.stock_ticks  where symbol = 'NFLX' and date = 1 and trade < 2045d660-9415-11e5-9742-c53da2f1a8ec;

Cassandra：根据＆＃34; timeuuid选择记录条件＆＃34;

1 个答案: