我正在努力确保列表具有唯一的SSN。我得到的"属性名称无法自动确定表达式元素=>元件。请通过调用' WithName'"来指定自定义媒体资源名称。错误。我们能在这里知道我做错了吗?
using FluentValidation;
using FluentValidation.Validators;
public class PersonsValidator : AbstractValidator<Persons>
{
public PersonsValidator()
{
this.RuleFor(element => element)
.SetValidator(new SSNNumbersInHouseHoldShouldBeUnique<Persons>())
.WithName("SSN");
.WithMessage("SSN's in household should be unique");
}
}
public class SSNNumbersInHouseHoldShouldBeUnique<T> : PropertyValidator
{
public SSNNumbersInHouseHoldShouldBeUnique()
: base("SSN's in household should be unique")
{
}
protected override bool IsValid(PropertyValidatorContext context)
{
var persons = context.Instance as Persons;
try
{
if (persons == null)
{
return false;
}
var persons = persons.Where(element => element.SSN.Trim().Length > 0);
var allSSNs = persons.Select(element => element.SSN.Trim());
if (allSSNs.Count() > allSSNs.Distinct().Count())
{
return false;
}
return true;
}
catch (Exception ex)
{
return false;
}
}
}
public class Persons : List<Person>
{}
public class Person
{
public string SSN{ get; set; }
}
答案 0 :(得分:2)
我使用的是FluentValidation版本4.6。根据Jeremy Skinner(FluentValidation的作者),我需要至少5.6才能使用模型级规则(如RuleFor(element =&gt; element))。 作为一种解决方法,我在实际的类本身上添加了此验证,而不是创建验证类。希望这有助于某人。
using FluentValidation;
using FluentValidation.Results;
public class Persons : List<Person>
{
public void ValidateAndThrow()
{
var errors = new List<ValidationFailure>();
try
{
var persons = this.Where(element => element.SSN.Trim().Length > 0);
var allSSNs = persons.Select(element => element.SSN.Trim());
if (allSSNs.Count() > allSSNs.Distinct().Count())
{
var validationFailure = new ValidationFailure("UniqueSSNsInHouseHold", "SSN's in a household should be unique");
errors.Add(validationFailure);
}
}
catch (Exception ex)
{
}
if (errors.Any())
{
throw new ValidationException(errors);
}
}
}