来自Groovy的invokeMethod没有参数

时间:2010-08-16 22:59:33

标签: groovy

我有一些似乎工作正常的Java代码:

/**
 * Helper method
 * 1. Specify args as Object[] for convenience
 * 2. No error if method not implemented 
 * (GOAL: Groovy scripts as simple as possible)
 * 
 * @param name
 * @param args
 * @return
 */
Object invokeGroovyScriptMethod(String name, Object[] args) {
    Object result = null;
    try {
        result = groovyObject.invokeMethod(name, args);         
    } catch (exception) { // THIS HAS BEEN GROVIED...
        if (exception instanceof MissingMethodException) {
            if (log.isDebugEnabled()) {
                log.debug("invokeGroovyScriptMethod: ", exception);
            }
        } else {
            rethrow exception;
        }
    }
    return result;
}

Object invokeGroovyScriptMethod(String name) {
    return invokeGroovyScriptMethod(name, [ null ] as Object[]);
}

Object invokeGroovyScriptMethod(String name, Object arg0) {
    return invokeGroovyScriptMethod(name, [ arg0 ] as Object[]);
}

Object invokeGroovyScriptMethod(String name, Object arg0, Object arg1) {
    return invokeGroovyScriptMethod(name, [ arg0, arg1 ] as Object[]);
}

但是我遇到了这个方法的问题:

Object invokeGroovyScriptMethod(String name) {
    return invokeGroovyScriptMethod(name, [ null ] as Object[]);
}


groovy.lang.MissingMethodException: No signature of method: MyClass.getDescription() is   applicable for argument types: (null) values: [null]
Possible solutions: getDescription(), setDescription(java.lang.Object)

任何提示?

谢谢 米莎

1 个答案:

答案 0 :(得分:1)

我快速离开(摆脱日志位并用println替换它,因为我没有在我的测试中设置日志),我想出了这个不需要重载的版本invokeGroovyScriptMethod:

Object invokeGroovyScriptMethod( String name, Object... args = null ) {
  try {
    args ? groovyObject."$name"( args.flatten() ) : groovyObject."$name"()
  } catch( exception ) {
    if( exception instanceof MissingMethodException ) {
      println "invokeGroovyScriptMethod: $exception.message"
    } else {
      throw exception;
    }
  }
}

groovyObject = 'hi'
assert    'HI' == invokeGroovyScriptMethod( 'toUpperCase' )
assert     'i' == invokeGroovyScriptMethod( 'getAt', 1 )
assert '***hi' == invokeGroovyScriptMethod( 'padLeft', 5, '*' )

// Assert will pass (as we catch the exception, print the error and return null)
assert    null == invokeGroovyScriptMethod( 'shouldFail' )

修改

再次阅读问题,你说这是一个Java类吗?但后来这个问题似乎指出这是Groovy代码......

我担心如果这是Java,我可能会把你送错路径......