Question

我在VS 2015中创建了一个示例ASP.NET MVC网站，在视图中我使用扩展Ajax.BeginForm将登录凭据发布到控制器，并且在OnSuccess回调中我想检查服务器错误以及是否有任何显示用户错误 - 重定向到主页，这里是代码（它总是故意返回错误来测试回调）：

模型

[Required]
public string Username { get; set; }
[Required]
public string Password { get; set; }

查看

<script>
    function onLogInSuccess(result) {
        /*
          Instead of getting here after returning the result from 
          Controller all the view(in the browser) is replaced with:
          {"status":"ERROR","message":"Invalid Email or Password.","returnUrl":"/"}
        */
        if (result.status === "OK") {
            window.location.href = result.returnUrl;
        } else {
            alert(result.message);
        }
    }

    $("#buttonLogIn").on('click', function (e) {
        $("#formLogIn").submit();
    });
</script>
<section id="loginForm">
@using (Ajax.BeginForm("LogIn", "Custom", null, new AjaxOptions { HttpMethod = "POST", OnSuccess = "onLogInSuccess" }, new { @class = "form-horizontal", role = "form", id = "formLogIn" }))
{
    @Html.AntiForgeryToken()
    <h4>Login:</h4>
    <hr />
    <div class="form-group">
        <label id="loginValidation" class="col-md-12 validation-label"></label>
    </div>
    <div class="form-group">
        <label class="col-md-12 control-label" for="LogInUsername">Username</label>
        <div class="col-md-12">
            <input class="form-control" id="LogInUsername" name="Username" type="text" value="" />
        </div>
    </div>
    <div class="form-group">
        <label class="col-md-12 control-label" for="LogInPassword">Password</label>
        <div class="col-md-12">
            <input class="form-control" id="LogInUsername" name="Password" type="password" value="" />
        </div>
    </div>
    <div class="form-group">
        <div class="col-md-offset-4 col-md-12">
            <input type="button" id="buttonLogIn" value="Log in" class="btn btn-default" />
        </div>
    </div>
}
</section>

控制器

[HttpPost]
[ValidateAntiForgeryToken]
public JsonResult LogIn(LoginModel Credentials)
{
    string returnUrl = "/";
    string status = AsyncRequestStatus.ResultError; //"ERROR"
    string message = "Invalid Email or Password.";

    return Json(new { status = status, message = message, returnUrl = returnUrl });
}

Answer 1

如果您只显示LogIn()方法返回的json，那么因为您的视图中未包含jquery.unobtrusive-ajax.js文件。因此，Ajax.BeginForm()会回归正常提交

Answer 2

如果您从服务器端发送一些不同于200的状态代码，则会执行错误回调：

$.ajax({
    url: '/foo',
    success: function(result) {

    },
    error: function(XMLHttpRequest, textStatus, errorThrown) {
        alert('you will see this');
    }
});

查看此链接https://stackoverflow.com/a/4707762/3521012

Ajax.BeginForm的ASP .NET MVC问题用JSON数据替换所有视图内容

2 个答案: