使用cx_Freeze构建简单的matplotlib应用程序非常有用,但是当我尝试从Tkinter&amp ;;创建一个独立的可执行文件时,我遇到了一个问题。 Matplotlib应用程序。
这是一个重现错误的最小例子:
#!/usr/bin/env python
import matplotlib
matplotlib.use('TkAgg')
from numpy import arange, sin, pi
from matplotlib.backends.backend_tkagg import FigureCanvasTkAgg, NavigationToolbar2TkAgg
# implement the default mpl key bindings
from matplotlib.backend_bases import key_press_handler
from matplotlib.figure import Figure
import sys
if sys.version_info[0] < 3:
import Tkinter as Tk
else:
import tkinter as Tk
root = Tk.Tk()
root.wm_title("Embedding in TK")
f = Figure(figsize=(5, 4), dpi=100)
a = f.add_subplot(111)
t = arange(0.0, 3.0, 0.01)
s = sin(2*pi*t)
a.plot(t, s)
# a tk.DrawingArea
canvas = FigureCanvasTkAgg(f, master=root)
canvas.show()
canvas.get_tk_widget().pack(side=Tk.TOP, fill=Tk.BOTH, expand=1)
toolbar = NavigationToolbar2TkAgg(canvas, root)
toolbar.update()
canvas._tkcanvas.pack(side=Tk.TOP, fill=Tk.BOTH, expand=1)
def on_key_event(event):
print('you pressed %s' % event.key)
key_press_handler(event, canvas, toolbar)
canvas.mpl_connect('key_press_event', on_key_event)
def _quit():
root.quit() # stops mainloop
root.destroy() # this is necessary on Windows to prevent
# Fatal Python Error: PyEval_RestoreThread: NULL tstate
button = Tk.Button(master=root, text='Quit', command=_quit)
button.pack(side=Tk.BOTTOM)
Tk.mainloop()
# If you put root.destroy() here, it will cause an error if
# the window is closed with the window manager.
特别是from matplotlib.backends.backend_tkagg import FigureCanvasTkAgg, NavigationToolbar2TkAgg
似乎导致了这个问题。如果我运行自己的应用程序,我会得到同样的错误,就好像我在上面运行这个:
Traceback (most recent call last):
File "C:\Anaconda2\lib\site-packages\cx_Freeze\initscripts\Console.py", line 27, in <module>
exec(code, m.__dict__)
File "Calipso.py", line 25, in <module>
File "C:___.py", line 14, in <module>
from matplotlib.backends.backend_tkagg import FigureCanvasTkAgg
File "C:\Users\Grant\Documents\GitHub\vocal\calipso\build\exe.win32-2.7\matplotlib\backends\backend_tkagg.py", line 7, in <module>
from six.moves import tkinter_filedialog as FileDialog
File "C:\Anaconda2\lib\site-packages\six.py", line 203, in load_module
mod = mod._resolve()
File "C:\Anaconda2\lib\site-packages\six.py", line 115, in _resolve
return _import_module(self.mod)
File "C:\Anaconda2\lib\site-packages\six.py", line 82, in _import_module
__import__(name)
ImportError: No module named FileDialog
我的setup.py
看起来像是:
import os
import sys
from distutils.core import setup
import cx_Freeze
import matplotlib
base = "Console"
executable = [
cx_Freeze.Executable("Calipso.py", base = base)
]
build_exe_options = {"includes":["matplotlib.backends.backend_tkagg", "ccplot.algorithms",
"ccplot.hdf", "Tkinter", "tkFileDialog"],
"include_files":[(matplotlib.get_data_path(), "mpl-data")],
"excludes": ["collections.abc"],
}
cx_Freeze.setup(
name = "py",
options = {"build_exe": build_exe_options},
version = "0.0",
description = "standalone",
executables = executable
)
如何确保捆绑FileDialog
?
答案 0 :(得分:1)
找到了解决此问题的方法。问题是FileDialog
是一个独立于Tkinter的包,所以我的脚本现在看起来像:
import os
import sys
from distutils.core import setup
import cx_Freeze
import matplotlib
base = "Console"
executable = [
cx_Freeze.Executable("Calipso.py", base = base)
]
build_exe_options = {"includes":["matplotlib.backends.backend_tkagg", "ccplot.algorithms",
"ccplot.hdf"],
"packages:" ["Tkinter", "tkFileDialog"],
"include_files":[(matplotlib.get_data_path(), "mpl-data")],
"excludes": ["collections.abc"],
}
cx_Freeze.setup(
name = "py",
options = {"build_exe": build_exe_options},
version = "0.0",
description = "standalone",
executables = executable
)