给window.open弹出一个标题

Question

我正试图在window.penn中给出一个标题的弹出窗口。但是我没有这样做。有任何帮助或建议吗？

function view() {
    window.open(url,"_self");           
}

Answer 1

您可以在打开窗口后更改标题。

#try the code below, it is working.
fname = raw_input("Enter file name: ")
count=0
value = 0
sum=0
fh = open(fname)
for line in fh:
    if not line.startswith("X-DSPAM-Confidence:") : continue
    pos = line.find(':')
    num = float(line[pos+1:])
    sum=sum+num
    count = count+1    
print "Average spam confidence:", sum/count