我需要从反馈表中获取用户表中的user_id，firstname，lastname和feedback_id，comment，user_id和recipe_id，其中user_id来自user，等于user表中的user_id。
review.html的
<div class="items item item-avatar" ng-repeat="comment in feedbackdata">
<img src="img/asd.jpg">
<h2>{{comment.firstname}} {{comment.lastname}}</h2>// I don't know what to put here
<p>{{comment.feedback_id}}</p>
<p>{{comment.comment}}</p>
<p>{{comment.user_id}}</p>
<p>{{comment.recipe_id}}</p>
Controller.js
.controller('CommentCtrl', function($scope, CommentList,$state,$location,SessionService,getFeedbackService) {
$scope.userdata = SessionService.getObject('userdata');
$scope.newComment={};
$scope.newComment.userID = $scope.userdata.user_id;
getFeedbackService.all().then(function(payload) {
$scope.feedbackdata = payload.data;
console.log(payload);
});
$scope.addComment = function(){
CommentList.add($scope.newComment);
console.log($scope.newComment);
};
})
Service.js
.factory('getFeedbackService', function($http){
return {
all: function() {
return $http.get("http://localhost/admin-recipick/api/Main/get_feedback_data");
}
};
});
main.php
public function get_feedback_data()
{
$postdata = json_decode(file_get_contents("php://input"));
$feedback = $this->User_model->feedback_data();
echo json_encode($feedback);
}
user_model.php
public function feedback_data()
{
$this->db->select('*');
$this->db->from('feedback')
$this->db->join('user','user.user_id = feedback.user_id');
$query = $this->db->get();
return $query->result_array();
}