Question

我试图重构我编写的Google AdWords脚本的一部分，以便不必重复if语句，我希望我可以通过＆的实例动态更新＃34;这＆＃34 ;.但是，我正在接收＆＃34;无法在对象firstKeywords中找到函数push。（第34行）＆＃34;错误。当我简单地插入＆＃34; firstKeywords.push＆＃34;而不是＆＃34; this.keywordsArray.push＆＃34;该脚本有效。想知道是否有办法让这个＆＃34;这个＆＃34;实例被视为一个数组，或者是否还有另一种解决方法？

Error: this.keywordsArray.push

非工作脚本：

var firstKeywords = [];
var secondKeywords = [];
var thirdKeywords = [];

function main() {
  function testKeywords(adgr, keywordsArray) {
  this.adgr = adgr;
  this.keywordsArray = keywordsArray;
}


testKeywords.prototype.move = function () {
    var campaignIterator = AdWordsApp.campaigns()
        .withCondition("Status = ENABLED")
        .withCondition("Name CONTAINS_IGNORE_CASE 'High'")
        .get();
    while (campaignIterator.hasNext()) {
      var campaign = campaignIterator.next();

  var adGroupIterator = campaign.adGroups()
        .withCondition("Name CONTAINS_IGNORE_CASE 'Blogs'")
        .get();
    while (adGroupIterator.hasNext()) {
      var adGroup = adGroupIterator.next();
      var adGroupName = adGroup.getName();
  var keywordIterator = adGroup.keywords()
        .withCondition("SystemServingStatus = RARELY_SERVED")
        .get();
    while (keywordIterator.hasNext()) {
      var keyword = keywordIterator.next();
      var keywordText = keyword.getText();
      var adgroupArray = this.keywordsArray;
        if (adGroupName === this.adgr) {
          this.keywordsArray.push(keywordText);
          keyword.pause();
        }
    }
    }
    }
}

var test01 = new testKeywords("General Music Blogs", "firstKeywords");
var test02 = new testKeywords("Hip Hop Music Blogs", "secondKeywords");
var test03 = new testKeywords("Indie Music Blogs", "thirdKeywords");

test01.move();
test02.move();
test03.move();
}

以下脚本的工作方式正确，但重复了if语句。

var firstKeywords = [];
var secondKeywords = [];
var thirdKeywords = [];

function main() {
  function testKeywords() {
  var campaignIterator = AdWordsApp.campaigns()
        .withCondition("Status = ENABLED")
        .withCondition("Name CONTAINS_IGNORE_CASE 'High'")
        .get();
    while (campaignIterator.hasNext()) {
      var campaign = campaignIterator.next();

  var adGroupIterator = campaign.adGroups()
        .withCondition("Name CONTAINS_IGNORE_CASE 'Blogs'")
        .get();
  while (adGroupIterator.hasNext()) {
      var adGroup = adGroupIterator.next();
      var adGroupName = adGroup.getName();
  var keywordIterator = adGroup.keywords()
        .withCondition("SystemServingStatus = RARELY_SERVED")
        .get();
    while (keywordIterator.hasNext()) {
      var keyword = keywordIterator.next();
      var keywordText = keyword.getText()
        if (adGroupName === 'General Music Blogs') {
          firstKeywords.push(keywordText);
          keyword.pause();
        }
        if (adGroupName === 'Hip Hop Music Blogs') {
          secondKeywords.push(keywordText);
          keyword.pause();
        }
        if (adGroupName === 'Indie Music Blogs') {
          thirdKeywords.push(keywordText);
          keyword.pause();
        }
       } 
      }
     }   
 }
}

提前致谢。

Answer 1

在您的testKeyword中，您传递的是string文字，而不是object参考。

所以改变

var test01 = new testKeywords("General Music Blogs", "firstKeywords");
var test02 = new testKeywords("Hip Hop Music Blogs", "secondKeywords");
var test03 = new testKeywords("Indie Music Blogs", "thirdKeywords");

到

var test01 = new testKeywords("General Music Blogs", firstKeywords);
var test02 = new testKeywords("Hip Hop Music Blogs", secondKeywords);
var test03 = new testKeywords("Indie Music Blogs", thirdKeywords);

推送到此解决方法

1 个答案: