我有一个测试表单(见下文),如果我手动提交,(单击“提交”按钮),则会从操作脚本中返回XML列表。
我希望能够通过xmlHTTP传递当前包含在测试HTML表单中的XML。到目前为止没有运气。任何帮助,将不胜感激。
<form action="processorders.asp" method="post" name="Orders" target="_blank">
<textarea cols="80" rows="10" name="request">
<REQUEST Version="1.0">
<RequestID>06012005171718</RequestID>
<Command>Orders</Command>
<UserID>myuserID</UserID>
<Password>xyzuvw</Password>
<Status>all</Status>
<SecurityKey></SecurityKey>
<OrderStartNumber>2255</OrderStartNumber>
</REQUEST>
</textarea><br>
<input type="submit">
</form>
答案 0 :(得分:1)
未经测试,但您可以尝试这样的事情:
Dim objXMLHTTP, returncode, XMLstring
XMLstring = "<REQUEST Version=""1.0"">"
XMLstring = XMLstring & "<RequestID>06012005171718</RequestID>"
XMLstring = XMLstring & "<Command>Orders</Command>"
XMLstring = XMLstring & "<UserID>myuserID</UserID>"
XMLstring = XMLstring & "<Password>xyzuvw</Password>"
XMLstring = XMLstring & "<Status>all</Status>"
XMLstring = XMLstring & "<SecurityKey></SecurityKey>"
XMLstring = XMLstring & "<OrderStartNumber>2255</OrderStartNumber>"
XMLstring = XMLstring & "</REQUEST>"
' Create an xmlhttp object:
Set objXMLHTTP = Server.CreateObject("Microsoft.XMLHTTP")
' Or, for version 3.0 of XMLHTTP, use:
' Set xml = Server.CreateObject("MSXML2.ServerXMLHTTP")
' Open the connection to the remote server:
objXMLHTTPOpen "POST", "http://url.to.your/target", False
objXMLHTTP.Send cstr(XMLstring)
' Actually Sends the request and returns the data:
returncode = objXMLHTTP.responseText
Set objXMLHTTP = Nothing
' Now do with the returncode what you like (this is the response HTML form the target URL)
请注意: - 您通过不安全的HTTP线路发送用户名和密码数据 - XML未经过验证或解析,您可能需要通过XML解析器
运行它Rico Suave