当我点击其中一个字母时,将显示所选的一个字母,其余部分应隐藏。
不知何故,代码不起作用。我使用的是jQuery。
$("#r-learn-more").click(function() {
alert("Handler for .click() called.");
});
$("#r-book-viewing").click(function() {
$("#bb").attr("display", "block");
});
$("#r-closing-price").click(function() {
alert("Handler for .click() called.");
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
<div class="fieldset-content">
<div class="radio">
<input type="radio" value="one" name="radiogroup1" id="r-learn-more" checked="">
<label for="r-learn-more">a</label>
</div>
<div class="radio">
<input type="radio" value="two" name="radiogroup1" id="r-book-viewing">
<label for="r-book-viewing">b</label>
</div>
<div class="radio">
<input type="radio" value="three" name="radiogroup1" id="r-closing-price">
<label for="r-closing-price">c</label>
</div>
</div>
<div id="aa" style="display: block;">a</div>
<div id="bb" style="display: none;">b</div>
<div style="display: none;">c</div>
&#13;
答案 0 :(得分:0)
一般情况下,您尝试使用$("#bb").attr('display','block')
,必须是$("#bb").css("display","block");
也许更好的方法是使用类似的东西:
<div class="fieldset-content">
<div class="radio">
<input type="radio" data-show="aa" value="one" name="radiogroup1" id="r-learn-more" checked="">
<label for="r-learn-more">a</label>
</div>
<div class="radio">
<input type="radio" data-show="bb" value="two" name="radiogroup1" id="r-book-viewing">
<label for="r-book-viewing">b</label>
</div>
<div class="radio">
<input type="radio" data-show="cc" value="three" name="radiogroup1" id="r-closing-price">
<label for="r-closing-price">c</label>
</div>
</div>
<div id="aa" class='item' style="display: block;">a</div>
<div id="bb" class='item' style="display: none;">b</div>
<div id="cc" class='item' style="display: none;">c</div>
和JS
var $items = $('.item');
$(':radio').on('change', function () {
var $item = $('#' + this.dataset.show);
$items.not($item).css('display', 'none');
$item.css('display', 'block');
});
答案 1 :(得分:0)
试试这个
$('.radio input').change(function(event){
$('.alphabet-letter').hide();
$('#'+$(this).data('id')).show();
}).first().prop('checked', true).trigger('change');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
<div class="fieldset-content">
<div class="radio">
<input type="radio" value="one" name="radiogroup1" id="r-learn-more" data-id="aa">
<label for="r-learn-more">a</label>
</div>
<div class="radio">
<input type="radio" value="two" name="radiogroup1" id="r-book-viewing" data-id="bb">
<label for="r-book-viewing">b</label>
</div>
<div class="radio">
<input type="radio" value="three" name="radiogroup1" id="r-closing-price" data-id="cc">
<label for="r-closing-price">c</label>
</div>
</div>
<div id="aa" class="alphabet-letter">
a
</div>
<div id="bb" class="alphabet-letter">
b
</div>
<div id="cc" class="alphabet-letter">
c
</div>
答案 2 :(得分:0)
只有一个“结果”div才会更容易?
像这样的东西
编辑:要将“a”显示为默认值,您只需在结果div中输入“a”,或者在加载时,您可以获得所选单选按钮选项的文本(在这种情况下,您不使用该值)根据代码段中的编辑
$('#result').text($('input:radio[name=radiogroup1]:checked').parent().text());
$( ".radio input" ).click(function() {
var label = $("label[for='"+$(this).attr('id')+"']");
console.log(label);
console.log(label.html());
$('#result').text(label.html());
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
<div class="fieldset-content">
<div class="radio">
<input type="radio" value="one" name="radiogroup1" id="r-learn-more" checked="">
<label for="r-learn-more">a</label>
</div>
<div class="radio">
<input type="radio" value="two" name="radiogroup1" id="r-book-viewing">
<label for="r-book-viewing">b</label>
</div>
<div class="radio">
<input type="radio" value="three" name="radiogroup1" id="r-closing-price">
<label for="r-closing-price">c</label>
</div>
</div>
<div id="result" style="display: block;">
<!--Alernative to load the text by jquery you could just put here "a"-->
</div>