我在python中遇到了这个简单的国际象棋代码的一些问题。这是每周作业的一部分;这是我到目前为止所得到的:
from math import sqrt
from random import randint,shuffle,seed
def rand_pos():
return [randint(0,7),randint(0,7)]
#first, classes defining the kings and the rook;
#their only attribute is a randomly generated position on the chessboard.
#Each of them has its special print method that will be used in the Chessboard (Scacchiera) class.
class W_king:
def __init__(self,coord=rand_pos()):
self.coord=coord
self.x=coord[1]
self.y=coord[0]
def __repr__(self):
return "R"
class B_king:
def __init__(self,coord=rand_pos()):
self.coord=coord
self.x=coord[1]
self.y=coord[0]
def __repr__(self):
return "r"
class Rook:
def __init__(self,coord=rand_pos()):
self.coord=coord
self.x=coord[1]
self.y=coord[0]
def __repr__(self):
return "T"
#the following will be used to calculate the distance between the kings and between a king and the rook;
#I'll use it in the while statements later in the Scacchiera class to check if the kings are generated too near or stuff
def distance(n1,n2):
return sqrt(sum((n1.coord[i]-n2.coord[i])**2 for i in [0,1]))
class Scacchiera:
def __init__(self,w_king=W_king(),b_king=B_king(),rook=Rook(),boxes=[[" " for y in range(8)] for x in range(8)]):
self.w_king=w_king
self.b_king=b_king
self.rook=rook
self.boxes=boxes
#here it is: while the two kings are generated too near,
#get the black king new coordinates
while distance(self.b_king,self.w_king)<2:
self.b_king.coord=[randint(0,7),randint(0,7)]
#...and, while the white king (or the black king) and the rook have the same coordinates
#or the black king is in the rook's sight,
#get a new pair of coordinates for the rook:
while self.w_king.coord==self.rook.coord or self.b_king.coord==self.rook.coord or self.rook.x==self.b_king.x or self.rook.y==self.b_king.y:
self.rook.coord=[randint(0,7),randint(0,7)]
print distance(self.b_king,self.w_king) #to check, just for me
#the function conv switches to the chessboard's coordinates e.g. e4, h5, etc
print conv(self.w_king.coord),conv(self.b_king.coord),conv(self.rook.coord)
def __repr__(self):
#self.boxes is an array of blank spaces " ",
#and in the right place the kings and the rook are placed
scacchiera=self.boxes[:]
scacchiera[self.w_king.x][self.w_king.y]=self.w_king
scacchiera[self.b_king.x][self.b_king.y]=self.b_king
scacchiera[self.rook.x][self.rook.y]=self.rook
return "\n".join([str(8-i)+" "+" ".join(str(scacchiera[i][j]) for j in range(8)) for i in range(8)])+"\n "+" ".join([chr(97+k) for k in range(8)])
def check(self,king):
#no need for this for now
return self.rook.x==king.x or self.rook.y==king.y
def black_legal_moves(self,mossa):
future_king=B_king([self.b_king.y+mossa[0],self.b_king.x+mossa[1]])
if distance(self.w_king,future_king)<2 or self.check(future_king):
return False
else:
return True
def new_mossa_random(self):
#this method chooses randomly a new position for the black king from the list of adjacent cells
#and tests if it's legal with the method above. If it's not, it deletes it from the list and re-tries
moves_list=[[self.b_king.y+hor,self.b_king.x+ver] for ver in [-1,0,1] for hor in [-1,0,1] if not hor==ver==0]
shuffle(moves_list)
move=moves_list[0]
#while it's not legal or the coordinates are out of the board:
while not self.black_legal_moves(move) or not 0<=move[0]<=7 or not 0<=move[1]<=7:
del moves_list[0]
if not moves_list:
return None
move=moves_list[0]
return move
def conv(coord):
return [chr(coord[0]+97),8-coord[1]]
#you just need to run it:
seed()
scacchiera=Scacchiera()
print scacchiera
print conv(scacchiera.new_mossa_random())
问题是两个:
while
上。NB :按照以下顺序打印PC上的脚本:
两位国王之间的距离,
棋盘上的坐标:白王,黑王,然后是车
棋盘上有棋子
黑王的新随机动作的坐标。
如果我应该添加其他信息,请告诉我。
答案 0 :(得分:1)
如果发生碰撞,您正在更改作品上的coord
成员。但 的位置也存储在x
和y
中,且未更新。
我建议您只在课程中保留x
和y
或仅coord
。如果您想获得幻想,可以保留coord
并将x和y设为properties by using @property
。
答案 1 :(得分:0)
答案 2 :(得分:0)
感谢您的帮助!最后,我删除了国王和车队的课程;它们毫无意义,我只需要一本字典,就像这里的代码一样。
这是我经历的解决方案
{% for project in object_list %}
<li><a href="{% url 'projects:detail' project.id %}">{{ project.name }}</a></li>
{% endfor %}