Question

我有一个带有多个指针的类，我想在响应中返回它们的完整对象（比如SQL中的连接）。下面的示例执行此操作，但它返回JSON而不是Parse对象。如何从指针返回包含每个Parse对象的对象数组，而不对每个指针执行额外的查询？

    query.find().then(function(results){
        /* Go Through Each Comment*/
        var commentsArray = new Array();
        for(i in results){
            /* Set obj to current comment*/
            var obj = results[i];
            /* Get Post's Name */
            var postName = obj.get("post").get("postName");
            /* Get Post's Message */
            var postMsg = obj.get("post").get("postMsg");
            /* Get Post Author's Name */
            var authorName = obj.get("post").get("postAuthor").get("name");
            /* Get Comment's Message */
            var commentMsg = obj.get("msg");
            /* Get Comment's Author*/
            var commentAuthor = obj.get("user").get("name");

            /* Let's Put the Comment Information in an Array as an Object*/
            commentsArray.push({
                post:{
                    name: postName,
                    msg: postMsg
                },
                author: authorName,
                comment: {
                    author: commentAuthor,
                    msg: commentMsg
                }
            });
        }
    })

编辑（我在客户端使用Swift构建）：

var query = new Parse.Query("Profile");

query.equalTo("objectId", objectId);

query.find().then(function(profile) {
  response.success(profile)  // Returns profile parse object
}, function(error) {
  response.error(error);
});


//RETURNS
"<Profile: 0x153f96570, objectId: HKdukNBlmA, localId: (null)> {\n}"



Parse.Cloud.define("getProfiles", function(request, response) {
  var query = new Parse.Query("Profile");

  query.include("friendId");

  query.find().then(function(profiles) {
    var res = [];

    profiles.forEach(function(profile) {
      var obj = {
        firstName: profile.get("firstName"),
        lastName: profile.get("lastName"),
        age: profile.get("age"),
        gender: profile.get("gender")
      };

      obj.friend = {
        firstName: profile.get("friendId").get("firstName"),
        lastName: profile.get("friendId").get("lastName"),
      };

      res.push(obj);
    });

    response.success(res);
  }, function(error) {
    response.error("Error: " + error.code + " " + error.message);
  });
});


// RETURNS
[{
  firstName: "bob",
  lastName: "smith",
  age: 19,
  gender: male
  friend: {
    firstName: "tim",
    lastName: "wang",
  }
},
{
  firstName: "chris",
  lastName: "scalia",
  age: 24,
  gender: male
  friend: {
    firstName: "ben",
    lastName: "calder",
  }
}]

我更喜欢前者。

Answer 1

调用者正在获取部分对象（只是一些属性），因为云函数使用它构造的一些属性进行响应。要获取解析对象，请返回解析对象...

Parse.Cloud.define("getProfiles", function(request, response) {
    var query = new Parse.Query("Profile");
    query.include("friendId");
    query.find().then(function(profiles) {
      response.success(profiles);
    }, function(error) {
      response.error("Error: " + error.code + " " + error.message);
    });
});

当然，这并不需要是云函数，因为它不会向查询添加任何值。客户端可以运行查询。

另请注意，我见过的另一件事，特别是快速作者调用解析，是一种奇怪的习惯，即进行查询，获取一个PFObjects数组作为响应，然后迭代这些对象并仅存储一些本地数组中的属性。这通常是一个错误，因此，在我看来，您的客户应该看起来像这样......

// no need to call a cloud function that just does a query
var query = PFQuery(className:"Profile")
query.includeKey("friendId")
query.findObjectsInBackgroundWithBlock { (objects: [PFObject]?, error: NSError?) -> Void in
    if error == nil {
        // don't iterate the objects here, saving bits of them in an array
        // have an instance var that is an array of PFObjects
        self.objects = objects;
    } else {
        print("Error: \(error!) \(error!.userInfo)")
    }
}

解析 - JavaScript指针查询，从指针返回解析对象

1 个答案: