这是python，我使用的是空闲版本3.4.2。 所以目前我的代码有效，但我想调整它以便能够： 保存名称的最新三个分数（因为它们重新运行代码并且分数保存在文本文件中）。然而，存在一个问题，无论输入什么“名称”，它都会用分数保存在自己的行上，而不是“附加”（我知道这是因为它不是以列表/字典的形式保存，而是如何我这样做了？ - 或者我读到你可以“拆分”这条线？）
这是我的第一个问题，如果有人能提供帮助，我会非常感激，我是python的新手，所以这对我来说是一个挑战！任何意见或建议都非常欢迎！
import random #import module
print("What is your name?") #prints writing in brackets
name = input().title() #Capitalizes the first letter of the word inputted
print("What class are you in? (Enter 1, 2 or 3)") #asks the user to input a number
while True:
try:
class_number = int(input()) #asks for an integer input from user
except ValueError:
print("Sorry, I didn't understand that, please try again") #print statement
continue
if class_number > 3: #if input is more than 3
print("SORRY but that class isn't recognised, try again") #print statement
continue
else:
print ("Hello,", name, "from class", class_number, "welcome to my quiz") #prints writing in brackets and anything saved in the variable "name" and "class_number"
break #break out of loop
score = 0 #sets the variable "score" to zero
question = 0 # sets the variable "question" to zero
while question < 3:#If questions (intitally set to 0) is smaller than 10, carry out this function
question +=1 # add one to the value of "question"
maths = random.randint(1,3) #randomly generate a number from 1-3 and store as "maths"
num1 = random.randint(1,10)#randomly generate an integer from 1-10 and store as "num1"
num2 = random.randint(1,10)#randomly generate a second integer from 1-10 and store as "num2"
if maths == 1: #if the number generated is 1
print(num1, "+", num2) #prints num1 + num2
ans = num1 + num2 #sets "ans" to equal the value of num1 added to num2
elif maths == 2: #if the number generated is 1
print(num1, "*", num2) #print num1 multiplied by num2
ans = num1 * num2 #sets "ans" to equal the value of num1 multiplied by num2
else: #else run this part of code
print(num1, "-", num2) #print num1 subtracted by num2
ans = num1 - num2 #sets "ans" to equal the value of num1 subtracted by num2
while True:
try:
user_ans = int(input()) #user inputs answer to question
except ValueError: #runs when the user input is no an integer
print ("SORRY but that answer isn't recognised, try again")
else:
break
if user_ans == ans:
score+=1
print("Well done, you are CORRECT")
else:
print("SORRY, you are INCORRECT") #print writing in brackets
print("The correct answer was", ans)
if score == 10: #run this part of code if "score" equals 10
print("fantastic", name, "you got full marks!") #print statement and name
elif score >= 6: #run this part of code if "score" is larger than or equal to 6
print("well done, there's some improvement to be done here though", name, "you got", score, "/10")# then print statement and score
elif score <=5: #run this part of code if "score" is smaller than or equal to 5
print("hmm, maybe some more practise would be beneficial", name, "you got", score, "/10") #then print statement and score
class_number = str(class_number) + ".txt" #this adds '.txt' to the end of the file (therefore creating a text file) so it can be used to create a file under the name of the class
file = open(class_number, 'a') #opens the file in 'append' mode so you don't delete all the information
file.write(str(name + " : ")) #writes the name and ":" to file
file.write(str(score)) #writes the score to file
file.write('\n')#writes the score to the file
file.close()#safely closes the file to save the information
view = int(input("would you like to view the scores? If yes, press 1 or not press 2"))
if view == 1:
exit
elif view == 2:
exit #to be completed
答案 0 :(得分：1)
如果您想将用户的分数保存到列表中......
my_list = []
my_list.append(score)
您可能希望在游戏开始前阅读文件。然后，您需要使用文本文件中的分数填充列表。
with open(class_number) as scorefile:
for line in scorefile:
my_list.append(line)
最后，当游戏结束时，您想要将用户的分数添加到文件中。在这种情况下，我会保持简单，并且不包括该人的姓名，但您仍然可以将该行添加到列表中。
f = open(class_number 'w')
f.write("\n" + score)
f.close()
然后，如果他们查看分数，只需打印my_list的值，用新行分隔列表中的每个元素。
答案 1 :(得分：1)
如果你想让它保持人类可读性，请将它写在json文件中：
import json
your_dictonary = {"my_key":"one_value"}
str_to_save = json.dumps(your_dictonary)
# Then write it to a file as you did before
加载几乎一样容易：
json.loads(file_content) # after you read the file as usual
答案 2 :(得分：0)
使用pickle模块存储您的数据。将您的user => score关系组织到字典中，然后调用pickle.dump(filename, theDict)将其保存到文件中。
当您需要它时，请致电theDict = pickle.load(filename)，它将从pickle文件加载数据。这种方法比你必须设计自己的解析算法要好。
答案 3 :(得分：0)
如果您可以更改文件的外观，请尝试saving the file as json。
在代码的顶部，加载文件中的分数：
import json
with open('{}.txt'.format(class_number)) as f:
scores = json.load(f)
然后，您可以修改字典中的分数并写回文件：
scores[name] = score
with open('{}.txt'.format(class_number)) as f:
json.dump(scores, f)
此代码不会存储超过最新分数的内容，但您可以探索为每个名称保存多个分数的选项。我建议看看defaultdict。
答案 4 :(得分：0)
有些答案建议将分数存储为JSON（好主意）或腌制它们（糟糕的主意！it's dangerous）。这个答案假定您要保留平面文件，最早的格式。
您正在以附加模式打开文件，因此您将无法更改任何内容。要进行更改，您首先需要阅读文件：
try:
fileh = open(class_number, 'r')
oldlines = fileh.readlines()
fileh.close()
except IOError: # If we didn't find the file, there were no old scores
oldlines = []
请注意，这会读取所有行;如果你的文件变得非常大，它将不会全部适合内存，你应该逐行阅读并随时写。
对于每一行：
如果我们从最近的一行开始，跟踪最近的分数会稍微容易一些，所以让我们这样做：
updatedlines = []
recentscores = 0
for line in oldlines[::-1]: # go backwards, most recent line first
(lname, lscore) = line.split(" : ") # read the name and the score from the line; this will break if the name contains " : "
if lname == name:
recentscores += 1 # keep track of how many scores we have for this person
if recentscores <3:
updatedlines.append(line)
else:
updatedlines.append(line)
updatedlines = updatedlines[::-1] # put the lines back in the right order
最后，添加新分数。
updatedlines.append("%s : %d\n" % (name, score))
现在我们可以将这些行写回文件：
fileh = open(class_number, 'w')
fileh.writelines(updatedlines)
fileh.close()