Question

我正在尝试开发一个项目，其中我的android应用程序将一个IP地址和端口号发送到wcf Web服务：但我无法做到并且可以获得Web服务的响应??? IService.cs

        [OperationContract]
    [WebGet(UriTemplate = "Connection/{ipadress}/{port}")]
    bool Connection(string ipadress,string port);

Service.svc.cs

    public bool Connection(string ipadress, string port)
    {
        /*          */
            return true;

    }

Android代码

    public boolean Connection_Net() {
    String url_service = "http://algotimesheet.azurewebsites.net/Service1.svc/Connection/ipadress/port";
    URLConnection urlConnection;
    DataOutputStream dataOutputStream;
    DataInputStream dataInputStream;
    URL url;

    try {
        url = new URL(url_service);
        urlConnection = url.openConnection();
        urlConnection.setDoOutput(true);
        urlConnection.setDoInput(true);
        urlConnection.setUseCaches(false);
        urlConnection.setRequestProperty("Content-Type", "application/json");
        urlConnection.setRequestProperty("Host", "android.schoolportal.gr");
        urlConnection.connect();

        JSONObject jsonObject = new JSONObject();
        jsonObject.put("ipadress","192.168.1.1");
        jsonObject.put("port","4370");
        OutputStreamWriter outputStreamWriter = new OutputStreamWriter(urlConnection.getOutputStream());
        outputStreamWriter.write(jsonObject.toString());
        outputStreamWriter.close();


    } catch (MalformedURLException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    } catch (JSONException e) {
        e.printStackTrace();
    }

    return true;
}

Answer 1

如果发送JSON，则需要编写服务以期望对象并使用POST

[OperationContract]
[WebInvoke(Method="POST", 
    RequestFormat = WebMessageFormat.Json, 
    UriTemplate = "Connection")]
bool Connection(Data data);

public bool Connection(Data data)
{
    /*          */
        return true;

}

设计这样的对象：

public class Data()
{
    public string ip {get; set;}
    public string port{get;set;}
}

如果您想制作GET，则只需将值添加到URL

从android客户端向WCF WS发送两个参数

1 个答案: