我正在尝试阅读以下命令
返回的一些属性DBCC USEROPTIONS
如何在JDBC中使用以下命令?
List<ResultVO> list = getJdbcTemplate().query(sql, new ParameterizedBeanPropertyRowMapper<ResultVO>() {
@Override
public ResultVO mapRow(ResultSet rs, int rowNumber) throws SQLException {
System.out.println(rowNumber);
ResultVO v = new ResultVO();
v.setSetOption(rs.getString(0));
v.setValue(rs.getString(1));
//--
return v;
}
}, (List<String>) null);
它抛出异常如下:
Caused by: org.springframework.dao.TransientDataAccessResourceException: PreparedStatementCallback; SQL [SELECT DBCC USEROPTIONS]; The index 1 is out of range.; nested exception is com.microsoft.sqlserver.jdbc.SQLServerException: The index 1 is out of range.
at org.springframework.jdbc.support.SQLStateSQLExceptionTranslator.doTranslate(SQLStateSQLExceptionTranslator.java:106)
at org.springframework.jdbc.support.AbstractFallbackSQLExceptionTranslator.translate(AbstractFallbackSQLExceptionTranslator.java:72)
答案 0 :(得分:3)
错误消息的第一行表示您的代码尝试执行SQL语句
SELECT DBCC USEROPTIONS
但这不是有效的T-SQL语法。 T-SQL语句
DBCC USEROPTIONS
确实返回一个有效的ResultSet,如下面的vanilla JDBC代码所示:
try (Connection conn = DriverManager.getConnection(connectionUrl)) {
try (
Statement s = conn.createStatement();
ResultSet rs = s.executeQuery("DBCC USEROPTIONS")) {
ResultSetMetaData rsmd = rs.getMetaData();
for (int i = 1; i <= rsmd.getColumnCount(); i++) {
System.out.printf("[%s]: %s%n", rsmd.getColumnName(i), rsmd.getColumnTypeName(i));
}
System.out.println();
while (rs.next()) {
System.out.printf("%s: %s%n", rs.getString(1), rs.getString(2));
}
}
} catch (Exception e) {
e.printStackTrace(System.err);
}
产生
[Set Option]: nvarchar
[Value]: nvarchar
textsize: -1
language: us_english
dateformat: mdy
datefirst: 7
lock_timeout: -1
quoted_identifier: SET
ansi_null_dflt_on: SET
ansi_warnings: SET
ansi_padding: SET
ansi_nulls: SET
concat_null_yields_null: SET
isolation level: read committed
看起来您需要调整Spring JDBC代码才能执行DBCC USEROPTIONS
。